1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tresset [83]
2 years ago
15

An open flask sitting in a lab fridge looks empty, but we know that actually it is filled with a mixture of gases called air. if

the flask volume is 1.50 l, and the air is at standard temperature and pressure, how many gaseous molecules does the flask contain?
Chemistry
1 answer:
OLga [1]2 years ago
7 0
Use ideal gas law PV=nRT
at STP, pressure is 1atm and temperature is 273K (0 Celsius)
1×1.5L=n × 0.0821 × 273
n is moles and R is ideal gas law constant, always 0.0821
moles= 14.9422(6.02×10^23 molecules)=9.0×10^24 molecules
You might be interested in
The formula HCl stands for ____.
serious [3.7K]
HCl :

hydrochloric acid

answer A

hope this helps!
7 0
2 years ago
How would you describe an electron
avanturin [10]

Answer:

an electron is part of the 3 things that are in an atom, it has a negative charge

8 0
3 years ago
Help!! I have no idea what to do!
Anvisha [2.4K]
I dunno............................................

5 0
3 years ago
What is the standard enthalpy of a reaction for which the equilibrium constant is (a) doubled, (b) halved when the temperature i
Alexxandr [17]

Answer:

a) 48KJ

b) -48KJ

Explanation:

Given that;

ln(K2/K1) = ΔH°/R(1/T2 - 1/T1)

K2= equilibrium constant at T2

K1 = equilibrum constant at T1

R = gas constant

T1 = initial temperature

T2 = final temperature

When we double the equilibrium constant K1; K2 = 2K1

T1 = 310 K

T2 = 310 + 15 = 325 K

ln(2K1/K1) =- ΔH°/R(1/T2 - 1/T1)

ln2 = -ΔH°/8.314(1/325 - 1/310)

0.693 = -ΔH°/8.314(3.08 * 10^-3 - 3.2 * 10^-3)

0.693 = -ΔH°/8.314 (-0.00012)

0.693 = 0.00012ΔH°/8.314

0.693 * 8.314 = 0.00012ΔH°

ΔH° = 0.693 * 8.314/0.00012

ΔH° = 48KJ

b) K2 =K1/2

ln(K1/2/K1) =- ΔH°/R(1/T2 - 1/T1)

ln (1/2) = -ΔH°/8.314 (1/325 - 1/310)

-0.693 = -ΔH°/8.314  (-0.00012)

-0.693 = 0.00012ΔH°/8.314

-0.693 * 8.314 = 0.00012ΔH°

ΔH°= -0.693 * 8.314/0.00012

ΔH°= -48KJ

6 0
3 years ago
Proszę napisać wzór kwasu karboksylowego o 7 atomach węgla sumaryczny i strukturalny.
Mice21 [21]

Answer:

Explanation:

Carboxylic acids is a homologous series in which the compounds contain a functional group called the carboxyl group (-COOH). The general molecular formula for carboxylic acids is CnH2n+1COOH. Carboxylic acids contain at least one carboxyl group.

Or in Polish…

Kwasy karboksylowe to homologiczna seria, w której związki zawierają grupę funkcyjną zwaną grupą karboksylową (-COOH). Ogólny wzór cząsteczkowy dla kwasów karboksylowych to CnH2n + 1COOH. Kwasy karboksylowe zawierają co najmniej jedną grupę karboksylową.

8 0
3 years ago
Other questions:
  • What is the name of this hydrocarbon? 2–methylpentyne 2–dimethylpentene 2,3–dimethylpentane 3,2–dimethylpentane
    6·1 answer
  • a solid with a low melting point is most likely what? A.ionic B. covalent C. metallic or D. None of the above.
    5·1 answer
  • What are some renewable energy sources​
    8·2 answers
  • Convert 614 Cal to J. Only include the numerical value in your answer. Respond with the correct number of significant figures in
    12·1 answer
  • What is the molarity of a solution that contains 30 grams of naoh in 500 milliliters of solution?
    15·2 answers
  • The system that works with respiratory system for the exchange of gases to take place is..?​
    9·2 answers
  • Why do you think large differences in temperature between the wet bulb and dry bulb thermometers are possible only at higher tem
    15·1 answer
  • Food chains always begin with what type of organism? Why?
    10·1 answer
  • What is the IUPAC name of this compound?  ________ CH3-CHCl-CH2-CH2-Cl​
    10·2 answers
  • What is mean by saturated solution and unsaturated solution​
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!