1. This is a combustion reaction.<span>
<span>Combustion reactions can happen with the </span>presence of O</span>₂ <span>gas. O₂<span>
reacts with another element or compound and </span></span>oxidize<span> it. Here ethanol reacts with O₂<span> and produces </span></span>CO₂ and H₂O as products.<span> <span>Combustion is also called as </span></span>burning. <span>
2.
Reaction will shift to right. <span>
</span><span>If more CH</span>₃CH₂OH is added to the system, then the</span> amount of CH₃CH₂OH will increase.<span> <span>Then the equilibrium in the system </span></span>will be broken.<span> <span>To make the equilibrium again, the </span></span>added CH₃CH₂OH should be removed.<span> To do that system will consume more CH</span>₃CH₂<span>OH to make products which helps to decrease
the amount of ethanol. Hence,
the reaction will shift to right.<span>
3. The reaction
will shift to right.</span><span>
</span><span>If the water is extracted from the system, the </span>amount of water will decrease. <span>That means the </span>amount of products decrease. Then the system will try to gain equilibrium by increasing the water. To increase water the forward reaction should be enhanced. <span>Hence, the</span> reaction will shift to right.<span>
4. The reaction
will shift to right.
</span><span>This is an </span>exothermic reaction <span>since it </span>produces heat. If the produced heat is removed, then the system will be cold. To maintain the temperature, system has to increase the amount of heat produced. Then, the forward reaction should be
enhanced. Hence, the reaction
will shift to right.<span>
5. The Le
Chatelier's principle.
</span>Le Chatelier's principle says if a
condition changes in a system which was in an equilibrium state, the system
will try to gain equilibrium by correcting the changed condition back to
normal. Most of industries which make
chemicals use this principle</span>
Answer:
Each principal energy level above the first contains one s orbital and three p orbitals. A set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. Therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.
Explanation:
Answer:
<h2>73.53 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question we have

We have the final answer as
<h3>73.53 mL</h3>
Hope this helps you
Answer:

Explanation:
Hello.
In this case, given the heat of fusion of THF to be 8.5 kJ/mol and freezing at -108.5 °C, for the required mass of 5.9 g, we can compute the entropy as:

Whereas n accounts for the moles which are computed below:

Thus, the entropy turns out:

Best regards.