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scZoUnD [109]
3 years ago
8

NEEDS HELP ASAPPPP.

Mathematics
1 answer:
grandymaker [24]3 years ago
4 0

Answer:i think it is 8 i think

Step-by-step explanation:

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And if we solve for a we got

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The 95th percentile of the hip breadth of adult men is 16.2 inches.

Step-by-step explanation:

Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:

X \sim N(14.4,1.1)  

Where \mu=14.4 and \sigma=1.1

For this part we want to find a value a, such that we satisfy this condition:

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P(X   (b)

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P(X  

P(z

And we have:

z=1.64

And if we solve for a we got

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The 95th percentile of the hip breadth of adult men is 16.2 inches.

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