Saul recorded the number of different types of pets his friends have in the table shown below: Cats 3 Dogs 2 Rabbits 1 Guinea Pi
gs 2 Which of the following plots represents the data in the table? A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 3 crosses, Dog has 2 crosses, Rabbit has 3 crosses, and Guinea Pig has 2 crosses. The line is labeled Number of Pets, and title of graph is Pet Owners. A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 1 cross, Dog has 2 crosses, Rabbit has 1 cross, and Guinea Pig has 2 crosses. The line is labeled Number of Pets, and title of graph is Pet Owners. A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 2 crosses, Dog has 1 cross, Rabbit has 0 crosses, and Guinea Pig has 1 cross. The line is labeled Number of Pets, and title of graph is Pet Owners. A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 3 crosses, Dog has 2 crosses, Rabbit has 1 cross, and Guinea Pig has 2 crosses. The line is labeled Number of Pets, and title of graph is Pet Owners.
2 answers:
Answer:
The correct answer is:
A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 3 crosses, Dog has 2 crosses, Rabbit has 1 cross, and Guinea Pig has 2 crosses. The line is labeled Number of Pets, and title of graph is Pet Owners.
Step-by-step explanation:
The survey is given as:
Pet Frequency
Cats 3
Dogs 2
Rabbits 1
Guinea Pigs 2
When we will draw a line plot where the horizontal axis denote the pet and the cross above the pet represent the number of pets.
Hence, as the frequency of cat is three so there will be three cross above cat.
Similarly as the frequency of dogs is two so there will be two cross above dogs.
the frequency of rabbits is one so there will be one cross above rabbit.
the frequency of Guinea Pigs is two so there will be two cross above Guinea Pigs.
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Answer:
<h2>The year is 2010.</h2>Step-by-step explanation:
The population of wolves is given by P(t) = 80(0.98)t.
The study has began in the year of 2000 and will end in 2020.
The difference between 2000 and 2009 is 9 years and the difference between 2009 and 2020 is 11 years.
Hence, the maximum value of t is 11.
The domain is .
The population will be 80, that is P(t) = 80.
Hence, 0.98t = 1, or, t = ≅1.
In (2009 + 1) = 2010, the population of wolves will be 80.