Hi anyone have any idea i am confused

Mathematics

1 answer:

Kobotan [32]2 years ago

3 0

Answer:

3rd option

Step-by-step explanation:

y = x² + 2x - 35

consider the factors of the constant term (- 35) which sum to give the coefficient of the x- term (+ 2)

the factors are + 7 and - 5 , since

7 × - 5 = - 35 and 7 - 5 = + 2 , then

y = (x + 7)(x - 5) ← in intercept form

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Express the fractions 1/2, 3/16, and 7/8 with an LCD

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You first need to find the LCD (lowest common denominator). You will need to find the smallest number that is a multiple of all numbers that is the denominator (2, 16, 8). Or, to say it another way, all the numbers in the denominator need to be a factor of this number.

You can find this by first checking if the largest number that is the denominator-- in this case 16-- is already the LCD, which means 16 is divisible by all the other numbers.

If this does not work, then multiply all the numbers together to get the LCD-- since you multiplied them together, you know that they will all be factors of the product.

However, you will be able to see that 16 is indeed the lowest common denominator:

2 × 8=16

8 × 2=16

16 × 1=16

So, after you find the LCD, multiply both the numerator and the denominator by the number that you would need to multiply the denominator to get the LCD (the whole point is that you want to get the denominator to be the LCD, but to do that you need to multiply both the top and bottom by the same number to keep the fraction the same).

(1/2) x (8/8)= 8/16

(3/16) x (1/1)= 3/16

(7/8) x (2/2)= 14/16

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3 years ago

Verify that each of the following transformations preserves congruence and name the congruence transformation

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Pentagon A B C D E is reflected across the X-axis to form pentagon A B C D.

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Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

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Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).