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3 years ago

Using the information given, you have to prove the statement they ask you to.

Mathematics

2 answers:

igomit [66]3 years ago

4 0

1. DE || AB - Given
2. DE 1/2 AB - side splitter theorem
3. CD/CA = CE/CB - sst = proportioned sides

garik1379 [7]3 years ago

4 0

As DE // AB so, its property of a triangle ...., the line parallel to it's base divide the other two sides on proportion..

so,CD/CA = CE/CB

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Find the product. Simplify your answer.

statuscvo [17]

Answer:

1/5

Step-by-step explanation:

Factor x² - 5x - 6

x² - 5x - 6 = (x + 1)(x - 6)

$\frac{x-6}{(x+1)(x-6)}$

Cancel the common factor.

$\frac{1}{x+1}$

$\frac{1}{x+1}$ · $\frac{x+1}{5}$

$\frac{1*(x+1)}{5*(x+1)}$

Cancel the common factor.

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3 years ago

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John has $220 in his account and adds $25 to it each month Cheryl has $100 in her account and adds $35 each to her account. How

sammy [17]

Answer: In 12 months they will have the same amount, which will be $520.

Step-by-step explanation:

220 + 25m = 100 + 35m

m = month

Subtract 100 from each side

120 + 25m = 35m

Subtract 25m from each side

120 = 10m

Divide each side by 10

12 = m

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3 years ago

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a certain parallelogram has two pairs of parallel sides based on the following classifications is not correct

andreev551 [17]

A certain parallelogram has two pairs of parallel sides based on the following classifications is not correct Is Trapezoid

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3 years ago

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Find the equation of the tangent line to the curve (a lemniscate)

olya-2409 [2.1K]

Answer:

$m=\frac{9}{13}$ and $b=\frac{40}{13}$

Step-by-step explanation:

The equation of curve is

$2(x^2+y^2)^2=25(x^2-y^2)$

We need to find the equation of the tangent line to the curve at the point (-3, 1).

Differentiate with respect to x.

$2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})$

$4(x^2+y^2)(2x+2y\frac{dy}{dx})=25(2x-2y\frac{dy}{dx})$

The point of tangency is (-3,1). It means the slope of tangent is $\frac{dy}{dx}_{(-3,1)}$ .

Substitute x=-3 and y=1 in the above equation.

$4((-3)^2+(1)^2)(2(-3)+2(1)\frac{dy}{dx})=25(2(-3)-2(1)\frac{dy}{dx})$

$40(-6+2\frac{dy}{dx})=25(-6-2\frac{dy}{dx})$

$-240+80\frac{dy}{dx})=-150-50\frac{dy}{dx}$

$80\frac{dy}{dx}+50\frac{dy}{dx}=-150+240$

$130\frac{dy}{dx}=90$

Divide both sides by 130.

$\frac{dy}{dx}=\frac{9}{13}$

If a line passes through a points $(x_1,y_1)$ with slope m, then the point slope form of the line is

$y-y_1=m(x-x_1)$

The slope of tangent line is $\frac{9}{13}$ and it passes through the point (-3,1). So, the equation of tangent is

$y-1=\frac{9}{13}(x-(-3))$

$y-1=\frac{9}{13}(x)+\frac{27}{13}$

Add 1 on both sides.

$y=\frac{9}{13}(x)+\frac{27}{13}+1$

$y=\frac{9}{13}(x)+\frac{40}{13}$

Therefore, $m=\frac{9}{13}$ and $b=\frac{40}{13}$ .

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3 years ago

Which of the following is an algebraic expression that represents the phrase X increased by 20

iren2701 [21]

Answer:

The expression means that X+20

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2 years ago