Answer:
103°
Step-by-step explanation:
The marked angles have the same measure, so ...
14x+7 = 12x +17
2x = 10 . . . . . subtract 12x+7
x = 5 . . . . . . . divide by 2
(14x +7)° = 77°
∠CEA is supplementary to the marked angles:
∠CEA = 180° -77°
∠CEA = 103°
Answer:
Area of trapezium = 4.4132 R²
Step-by-step explanation:
Given, MNPK is a trapezoid
MN = PK and ∠NMK = 65°
OT = R.
⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).
Now, sum of interior angles in a quadrilateral of 4 sides = 360°.
⇒ x + x + 65° + 65° = 360°
⇒ x = 115°.
Here, NS is a tangent to the circle and ∠NSO = 90°
consider triangle NOS;
line joining O and N bisects the angle ∠MNP
⇒ ∠ONS =
= 57.5°
Now, tan(57.5°) = 
⇒ 1.5697 = 
⇒ SN = 0.637 R
⇒ NP = 2×SN = 2× 0.637 R = 1.274 R
Now, draw a line parallel to ST from N to line MK
let the intersection point be Q.
⇒ NQ = 2R
Consider triangle NQM,
tan(∠NMQ) = 
⇒ tan65° =
⇒ QM =
QM = 0.9326 R .
⇒ MT = MQ + QT
= 0.9326 R + 0.637 R (as QT = SN)
⇒ MT = 1.5696 R
⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R
Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).
⇒ A = (
) × (ST)
= (
) × 2 R
= 4.4132 R²
⇒ Area of trapezium = 4.4132 R²
Acute angle and a right angle makes a obtuse I learned this in 4th
Answer:
x= -12
Step-by-step explanation:
Simplifying
4x + 10 = 2x + -14
Reorder the terms:
10 + 4x = 2x + -14
Reorder the terms:
10 + 4x = -14 + 2x
Solving
10 + 4x = -14 + 2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2x' to each side of the equation.
10 + 4x + -2x = -14 + 2x + -2x
Combine like terms: 4x + -2x = 2x
10 + 2x = -14 + 2x + -2x
Combine like terms: 2x + -2x = 0
10 + 2x = -14 + 0
10 + 2x = -14
Add '-10' to each side of the equation.
10 + -10 + 2x = -14 + -10
Combine like terms: 10 + -10 = 0
0 + 2x = -14 + -10
2x = -14 + -10
Combine like terms: -14 + -10 = -24
2x = -24
Divide each side by '2'.
x = -12
Simplifying
x = -12