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lora16 [44]
2 years ago
6

The distance versus time plot for a particular object shows a quadratic relationship. Which column of distance data is possible

for this situation?
Time (s) / A. Distance (m) /B. Distance (m) /C. Distance (m) / D. Distance (m) / E. Distance(m)
0 / 0 / 2.00 / 9.00 / infinity / infinity
1 / 1.00 / 4.00 / 18.00 / 1.00 / 1.00
2 / 4.00 / 6.00 / 27.00 / 0.50 / 0.25
3 / 9.00 / 8.00 / 36.00 / 0.33 / 0.11
4 / 16.00 / 10.00 / 45.00 / 0.25 / 0.06
5 / 25.00 / 12.00 / 54.00 / 0.20 / 0.04
6 / 36.00 / 14.00 / 63.00 / 0.16 / 0.02


(A) column A
(B) column B
(C) column C
(D) column D
(E) column E
Mathematics
1 answer:
Viktor [21]2 years ago
3 0

Answer:

(A) column A

Step-by-step explanation:

The distance values in column A are:

0, 1, 4, 9, 16, 25 and 36

If you just look at these values, these are the squares of 0, 1, 2, 3, 4, 5 and 6 which shows that distance in column A versus time would show a quadratic plot.

For the values showing a quadratic relationship, the second differences in the values are constant. This means, if we find the differences of two consecutive terms for all the terms and then find the difference of the answers resulted in previous step, these should be a constant for the quadratic function.

Differences in the values of Columns A are:

1, 3, 5, 7, 9, 11

The difference in these differences are:

2, 2, 2, 2, 2

which is a constant. Since, the difference is being calculated two times, it is known as second difference. The second difference must be constant for a quadratic relationship. For the other columns, the second differences are not constant.

Therefore, the correct answer is option A.

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A realtor would like to create a 95% confidence interval for the average price of a house in Franklin County, Ohio. To accomplis
VMariaS [17]

Answer:

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=320128 represent the sample mean

\mu population mean (variable of interest)

\sigma=50324 represent the population standard deviation

n=529 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

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