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jeyben [28]
4 years ago
6

PLZ HELP FAST!!!

Mathematics
1 answer:
maxonik [38]4 years ago
7 0

Answer:

The range of possible values for the third side called c is;

11 > c or c < 11

Step-by-step explanation:

Here in this question, we are concerned with giving the range of the third side of the triangle.

What we will be using to get this range is the triangle inequality theorem.

Mathematically, the sum of the length of the two sides must be greater than the length of the third side.

So let’s call the third side c

Thus, the range of values we are to work with is;

5 + 6 > c

11 > c

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Step-by-step explanation:

Translations: When a figure is slid to another place on the coordinate grid (for example if i asked you to move the figure 2 units down and 4 units to the left)

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3 years ago
A water sprinkler sends water out in a circular pattern. How many feet away from the sprinkler can it spread water if the area f
otez555 [7]

Answer:

The sprinkler can spread water 18 feet away.

Step-by-step explanation:

We are given the following in the question:

Area formed by watering pattern = 1,017.36 square feet

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The sprinkler covers a circular area. We need to find the radius of this circular area to find the how far the sprinkler spread the water.

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Putting values, we get:

1017.36 = 3.14 r^2\\\\r^2 = \dfrac{1017.36}{3.14}\\\\r^2 = 324\\r = \sqrt{324} = 18\text{ feet}

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3 years ago
Please help please these are short answers
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Answer: The answers are given below.


Step-by-step explanation:  The calculations are as follows:

(19) Weight of the puppy last week is

W_\ell=2\dfrac{1}{2}~\textup{lb},

and weight of the puppy this week is

W_p=7\dfrac{1}{4}=\dfrac{29}{4}~\textup{lb}.

Therefore, the weight gained by the puppy is given by

W_g=W_p-W_\ell=\dfrac{29}{4}-\dfrac{5}{2}=\dfrac{29-10}{4}=\dfrac{19}{4}=4\dfrac{3}{4}~\textup{lb}.

(20) Time taken in Route 1 = 1 hour 30 minutes.

Time taken in Route 2 = 1 hour 45 minutes.

Time taken in Route 3 = 1 hour 35 minutes.

Time taken in Route 4 = 1 hour 25 minutes.

Since we want to spent the least amount of time on the bus, so we will be taking route 4.

(21) Time taken by Nazia to complete her language arts homework is

H_\ell=\dfrac{4}{9}~\textup{hr},

and the time taken by Nazia to complete her Mathematics homework is

H_m=\dfrac{2}{9}~\textup{hr}.

Therefore, Nazia takes more time to complete Language Arts homework, by

H=H_\ell-H_m=\dfrac{4}{9}-\dfrac{2}{9}=\dfrac{2}{9}~\textup{hr}.

(22) Quantity of Aluminium collected by Maya is

A_m=\dfrac{4}{20}=0.2~\textup{lb},

and the quantity of Aluminium collected by her friend Abigail is

A_a=\dfrac{7}{8}=0.87~\textup{lb}.

Therefore,

(a) Abigail collected more aluminium

and

(b) Total Aluminium collected by both the girls is

T=A_m+A_a=\dfrac{4}{20}+\dfrac{7}{8}=\dfrac{8+35}{40}=\dfrac{43}{40}~\textup{lb}.

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S_w=3\dfrac{1}{4}=3.25~\textup{in.},

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S_s=3\dfrac{4}{5}=3.8~\textup{in.}.

Therefore, quantity of snowfall was more on Sunday by

S=S_s-S_w=3\dfrac{4}{5}-3\dfrac{1}{4}=\dfrac{19}{5}-\dfrac{13}{4}=\dfrac{76-65}{20}=\dfrac{11}{20}~\textup{in.}.

Thus, all the questions are answered.

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