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2 years ago

What is the value of 6 3/4(-11)?

Mathematics

2 answers:

yuradex [85]2 years ago

3 0

-74.25 or -72 1/4 (if ur multiplying by -11, if u subtracting -11 then it would be -4 1/4

Vedmedyk [2.9K]2 years ago

3 0

Answer:

$=-\frac{99elsov}{2}$

Step-by-step explanation:

$\mathrm{Compute\:an\:expression\:comprised\:of\:factors\:that\:appear\:either\:in\:}solve\mathrm{\:or\:}6\frac{3}{4}\left(-11\right)$

$=-\frac{99elsov}{2}$

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3 years ago

I've tried solving this but I'm stuck -8=2/x

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Answer:

-0.25

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5 0

3 years ago

Read 2 more answers

A room is 5 meters by meters . How many square 14-inch tiles will it take to floor the room ? I meant to say a room is 5 meters

lesya [120]

Given:

Room is 5 meters by 8 meters.

Measure of squaree tiles is 14-inch.

$\begin{gathered} \text{Area of the room=5}\times8 \\ \text{Area of the room=}40m^2 \end{gathered}$ $1m^2=1550inch^2$ $\begin{gathered} \text{Area of each tile=14}\times14 \\ \text{Area of each tile=}196inch^2 \end{gathered}$ $\begin{gathered} \text{Number of tiles to floor the room=}\frac{40\times1550}{196} \\ \text{Number of tiles to floor the room}=316.3265 \end{gathered}$

Approximately 316 tiles are required to floor the room.

8 0

1 year ago

A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a

Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\$

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)$ [as x+y=14]

$\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\$

$\Rightarrow x =(25 \times 14)/32=10.9375$ grams

and $y = 14-x= 14-10.9375=3.0625$ grams.

Hence, 10.9375 grams of 82% gold and 3.0625 grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\$

$\Rightarrow x =(50 \times 14)/57=12.28$ grams

and $y = 14-x= 14-12.28=1.72$ grams.

Hence, 12.28 grams of 82% gold and 1.72 grams of 50% gold added to make 14 grams of 75% gold.

3 0

2 years ago