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Gnoma [55]
2 years ago
14

Line B will be graphed on the same grid. The only solution to the system of linear equations formed by Line A and Line B will oc

cur when r = -4 and y = 7. Which equation could represent Line B?​

Mathematics
1 answer:
Nady [450]2 years ago
7 0

Answer:

Step-by-step explanation:

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In August 2003, 56% of employed adults in the United States reported that basic mathematical skills were critical or very import
Serga [27]

Answer:

Yes

Step-by-step explanation:

First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.

It has mean μ= np =  30×0.56=16.8

standard deviation s = √npq

sqrt(30×0.56×(1-0.56)) = 2.71

So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.

7 0
3 years ago
What is the least common denominator (LCD) for these fractions? 2/7 and 9/10
yanalaym [24]

Answer:

70

Step-by-step explanation:

7 and 10 = 70, This is the correct answer because 7 times 10 equals 70, and 10 times 7 equals 70 too, so 70 is the LCD

7 and 10 = 1, This is impossible because anything multiplied by 7 naturally does not get 1 as a answer, including 10 too. X

7 and 10 = 10, Only 10 times 1 equals 10, but 7 a natural whole number does not equal 10. X

7 and 10 = 35, Only 7 times 5 equals 35, but 10 times a whole number does not equal 35. X

4 0
3 years ago
Marsha's house is located on the coordinate plane below. Tasha's house is located 6 units from Marsha's house. Which of the foll
Gekata [30.6K]

B 4,2 because it is 6 units away from the point

3 0
2 years ago
Suppose the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars
GuDViN [60]

Answer:

Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

Step-by-step explanation:

We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.

<em>Let X = incomes for the industry</em>

So, X ~ N(\mu=95,\sigma^{2}=5^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = mean income of firms in the industry = 95 million dollars

            \sigma = standard deviation = 5 million dollars

So, probability that a randomly selected firm will earn less than 100 million dollars is given by = P(X < 100 million dollars)

    P(X < 100) = P( \frac{X-\mu}{\sigma} < \frac{100-95}{5} ) = P(Z < 1) = 0.8413   {using z table]

                                                     

Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

5 0
3 years ago
Which expression are equivalent to 5x-15? Check all that apply
scZoUnD [109]
1,3 is correct can i be brainliest


5 0
3 years ago
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