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adoni [48]
3 years ago
6

Reggie can line a football field in 120 minutes. Rosalinda can line a football field in 80 minutes. If they work together, how m

any minutes does it take them to line a football field?
Mathematics
2 answers:
Oduvanchick [21]3 years ago
7 0

Answer:

48 minutes

Step-by-step explanation:

Reggie can line 1/120 of a football field in 1 minute while Rosalinda can line 1/80 of a football field in 1 minute.

Therefore adding the 2 fractions we get; that BOTH of them can line 1/120+1/80 of a field in 1 minute. 1/120+1/80=1/48.

1/48 of a field can be done in a minute, so it would take them 48 minutes to do 48/48 or 1 whole field.

wel3 years ago
6 0

Answer:

48 minutes

Step-by-step explanation:

Given that;

Rosalinda can line the football field in 80 minutes

Reggie can line the football field in 120 minutes

Lets assume that if they work together, they will take T minutes to line the football field

Hence;

Thus in 1 minute, Rosalina can line 1/80 of the field where as Reggie can line 1/120 of the field

\frac{1}{T} =\frac{1}{120} +\frac{1}{80} \\\\\frac{1}{T} =\frac{2+3}{240}\\\\

The sum of the two fractions will represent the size of the field that can be lined in 1 minute.

\frac{1}{T} =\frac{5}{240} \\\\\frac{1}{T} =\frac{1}{48} \\T= 48

The reciprocal of the sum of the two fractions will represent the time taken for both Rosalinda and Reggie to line the field.

Answer ; It will take them 48 minutes for them to line the football field

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What is an equation of the line that passes through the points (0, 3) and (5,-3)?
Arisa [49]

Answer:

The equation of the line that passes through the points (0, 3) and (5, -3) is y = -\frac{6}{5}\cdot x +3.

Step-by-step explanation:

From Analytical Geometry we must remember that a line can be formed after knowing two distinct points on Cartesian plane. The equation of the line is described below:

y = m\cdot x + b (Eq. 1)

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

m - Slope, dimensionless.

b - y-Intercept, dimensionless.

If we know that (x_{1},y_{1}) = (0,3) and (x_{2},y_{2})=(5,-3), the following system of linear equations is constructed:

b = 3 (Eq. 2)

5\cdot m + b = -3 (Eq. 3)

The solution of the system is: b = 3, m = -\frac{6}{5}. Hence, we get that equation of the line that passes through the points (0, 3) and (5, -3) is y = -\frac{6}{5}\cdot x +3.

5 0
3 years ago
Which expression is equivalent to 2 (14x-37+28x+12.2-5y-17.5)?
ziro4ka [17]

Answer:

A. 84x - 16y - 10.6

Explanation:

\sf \rightarrow 2(14x-3y+28x+12.2-5y-17.5)

\sf \rightarrow 2 (42x-8y-5.3)

apply distributive method: a(b + c) = ab + ac

\sf \rightarrow 2 (42x) -2(8y)-2(5.3)

\sf \rightarrow 84x -16y-10.6

7 0
1 year ago
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
Please solve with explanation
castortr0y [4]

Answer:

The amount of wood left is 36 9/16 in

Step-by-step explanation:

Here, we want to get the amount of wood left

To calculate this, we have to subtract what is cut and what is wasted from the original total length

So we have what is left as follows;

45 1/2 - 8 7/8 - 1/16

45 1/2 = 91/2

8 7/8 = 71/8

91/2 - 71/8 - 1/16

(728 - 142 - 1)/16

585/16 = 36 9/16 in

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3 years ago
What is the difference? Complete the equation.<br> -2 1/4 - (-3/4)
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Answer:

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Step-by-step explanation:

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