
is already in simplest form because 23 is a prime number, which means that it is only divisible by 1 and itself (23). Hope this helps! :)
Answer:
the first problem is - 85 and you continue from there
We have the price of a senior ticket is $4 and the price of a child ticket is $7
Step-by-step explanation:
We can form two equations, let the price of a senior ticket be s and the price of a child ticket be c.
We have from day 1:
A: 3s + 9c = 75
And from day 2:
B: 8s + 5c = 67
Now we can rewrite A as:
A: 24s + 72c = 600
And can rewrite B as:
B: 24s + 15c = 201
Now A-B can be written as:
A-B: 57c = 399
So c = 7
Now substituting this back into A we get:
A: 3s + 63 = 75
A: 3s = 12
So s = 4
We have the price of a senior ticket is $4 and the price of a child ticket is $7
The triangle lengths would be 14√2, 7√2 and 7√6.
The sides of a 45-45-90 triangle can be listed as t, t and t√2. The legs are each 14, so the hypotenuse will be 14√2.
This will also be the longest side of the 30-60-90 triangle. Its sides can be listed as t, 2t and t√3. Since the hypotenuse is the longest side, we have:
2t=14√2
Dividing both sides by 2, we have:
2t/2 = 14√2/2
t = 7√2
The remaining side will be t√3:
t = 7√2
t√3 = 7√2(√3) = 7√6
Answer:
Option 4) 
Step-by-step explanation:
we know that
If two figures are similar then the ratio of its areas is equal to the scale factor squared
Let
z------> the scale factor
x-----> the area of the dilated rectangle
y----> the area of the original rectangle
so

we have


substitute and solve for x

