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Vikki [24]
3 years ago
10

6-4x=(3-x) A) -2 B) 2 C) all real, numbers D) no solution

Mathematics
2 answers:
Semmy [17]3 years ago
6 0
6 - 4x = (3 - x)

Subtract 6 from both sides, as well as adding x to both sides.

-4x + x = 3 - 6

Add like terms.

-3x = -3

Divide both sides by -3.

x = 1

So, your answer is c) All real, numbers because all of the other answer choices are wrong. 

We know this because a) and b) are incorrect. To know if they are incorrect, you just plug in the numbers. When 2 and -2 are plugged into the equation, it is incorrect. So, you solve the equation, and you now know that it is not D) because there is a solution. 

So, once again, your answer is C.

~Hope I helped!~

Alenkasestr [34]3 years ago
4 0
Remember you can do anything to an equation as long as you do it to both sides

6-4x=3-x
add 4x to both sides
6=3+3x
minus 3 both sides
3=3x
divide both sides by 3
1=x
not an option
what
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6 0
3 years ago
I need help with this problem on the math test, It's due TONIGHT! Plz help me with my math
cricket20 [7]

Answer:

the first problem is - 85 and you continue from there

We have the price of a senior ticket is $4 and the price of a child ticket is $7

Step-by-step explanation:

We can form two equations, let the price of a senior ticket be s and the price of a child ticket be c.

We have from day 1:

A: 3s + 9c = 75

And from day 2:

B: 8s + 5c = 67

Now we can rewrite A as:

A: 24s + 72c = 600

And can rewrite B as:

B: 24s + 15c = 201

Now A-B can be written as:

A-B: 57c = 399

So c = 7

Now substituting this back into A we get:

A: 3s + 63 = 75

A: 3s = 12

So s = 4

We have the price of a senior ticket is $4 and the price of a child ticket is $7

5 0
3 years ago
What are the dimensions of the largest 30-60-90 triangle that will fit inside a 45-45-90 triangle with leg length 14in.? Sketch
Ksivusya [100]
The triangle lengths would be 14√2, 7√2 and 7√6.

The sides of a 45-45-90 triangle can be listed as t, t and t√2.  The legs are each 14, so the hypotenuse will be 14√2.

This will also be the longest side of the 30-60-90 triangle.  Its sides can be listed as t, 2t and t√3.  Since the hypotenuse is the longest side, we have:

2t=14√2

Dividing both sides by 2, we have:
2t/2 = 14√2/2
t = 7√2

The remaining side will be t√3:

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5 0
3 years ago
A rectangle with an area of 8 ft² is dilated by a factor of 4. What is the area of the dilated rectangle?
prohojiy [21]

Answer:

Option 4) 128\ ft^{2}

Step-by-step explanation:

we know that

If two figures are similar then the ratio of its areas is equal to the scale factor squared

Let

z------> the scale factor

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y----> the area of the original rectangle

so

z^{2}=\frac{x}{y}

we have

z=4

y=8\ ft^{2}

substitute and solve for x

4^{2}=\frac{x}{8}

x=16(8)=128\ ft^{2}

4 0
3 years ago
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vlabodo [156]

Answer:

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Step-by-step explanation:

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