Answer:
x = 35
Step-by-step explanation:
The segment from the vertex of the triangle is an angle bisector and divides the opposite side into 2 segments that are proportional to the other 2 sides, that is
=
( cross- multiply )
8x = 280 ( divide both sides by 8 )
x = 35
Answer:
1 cake and 6 pies
Step-by-step explanation:
Let c represent the number of cakes Alice and George can make. Likewise, let p represent the number of pies.
Then the amount of flour they need (in cups) is ...
3c + 2p . . . . cups of flour needed
And the amount of sugar needed is ...
2c + 1.5p . . . cups of sugar needed
__
They want to use all 15 cups of flour they have, and all 11 cups of sugar, so the amounts above need to match the amounts on hand:
3c + 2p = 15
2c + 1.5p = 11
We can solve these equations various ways. One of my favorite is to use a graphing calculator. (See attached) It tells us that Alice and George can make 1 cake and 6 pies with the flour and sugar they have.
_____
If you want to solve these equations algebraically, there are several methods for that, too. Here, we can multiply the first one by 2/3 and subtract the result from the second one:
(2c +1.5p) -(2/3)(3c +2p) = (11) -(2/3)(15)
2c +3/2p -2c -4/3p = 11 -10 . . . . . eliminate parentheses
1/6p = 1 . . . . . . . . . . . . . . . . . . . . . .collect terms
p = 6 . . . . . . . . . . . . . . . . . . . . . . . . multiply by 6
Substituting into the first equation gives ...
3c +2·6 = 15 . . . substitute 6 for p
3c = 3 . . . . . . . . subtract 12
c = 1 . . . . . . . . . . divide by 3
These values tell us Alice and George can make 1 cake and 6 pies with the flour and sugar they have.
<u>Given</u>:
Four coordinates lying on the 3rd quadrant of the Cartesian plane are as follows:
<u>Translation</u>:
Since you've been asked to translate the coordinates of the vertices 2 units right and 8 units up, you'll need to add 2 to its x-coordinate and 8 to its y-coordinate.
C'(–6, –5)
ㅤㅤ= C'(–6 + 2, –5 + 8)
ㅤㅤ= C'(–4, 3)
D'(–6, –3)
ㅤㅤ= D'(–6 + 2, –3 + 8)
ㅤㅤ= D'(–4, 5)
E'(–4, –3)
ㅤㅤ= E'(–4 + 2, –3 + 8)
ㅤㅤ= E'(–2, 5)
F'(–4, –5)
ㅤㅤ= F'(–4 + 2, –5 + 8)
ㅤㅤ= F'(–2, 3)
<u>Final </u><u>answer</u>:
