1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ksivusya [100]
3 years ago
11

Two cars raced at a race track. The faster car traveled 20 mph faster than the slower car. In the time that the slower car trave

led 165 miles, the faster car traveled 225 miles. If the speeds of the cars remained constant, how fast did the slower car travel during the race? Distance (mi) 165 Rate (mph) Time (h) 165 Slower Car Faster Car 225 + 20 225 + 20 55 mph 60 mph 75 mph 130 mph ​
Mathematics
1 answer:
kakasveta [241]3 years ago
8 0

Answer:

pano yan paturo

Step-by-step explanation:

hinde ko alam

You might be interested in
Mr. peter travels 130 miles in 2 hours. at this rate, how many miles will he travel in 30 minutes?
enyata [817]
Alright so basically what you have to do here is realize that 130 miles is 2 hours, so if you divide by 2, you’ll have 65 miles in one hour ,, so 6mph, and if you divide again by two, you have 32.5 miles ,, therefore he travels 32.5 miles in 30 minutes
4 0
3 years ago
Choose all that state the correct unit rate for each situation. 100 POINTS ASAP K12
Lorico [155]

Answer:

Please see the answers below:

Step-by-step explanation:

The wrong answers are deleted only the correct answers are listed below:

  • Ryan earns $45 for 5 hours of work. The unit rate is $9 for 1 hour.
  • Jenna can drive her car 110 miles on 5 gallons of gasoline. The unit rate is 22 miles per gallon.
  • Claire saves $320 in 16 weeks. The unit rate is $20 per week.

  • % increase in price of gas = [(New Price - Original Price) / Original Price] x 100

% increase in price of gas = [($2.48 - $2.18) / $2.18] x 100

% increase in price of gas = [$0.3 / $2.18] x 100

% increase in price of gas = 13.76%

7 0
3 years ago
Can someone pls help me with these equations
Zielflug [23.3K]

Answer:

1. y = -2x+5

2. y = 3/4 - 3

3. intercept = -5 slope =  4/3

4. intercept = 1 slope = -1/2

5 0
3 years ago
An adolescent has a weight of 127 pounds. The doctor requires you to record the patient’s weight in kilograms. Convert 127 pound
olasank [31]

The amount of kilograms he weighs I think is 57.6062994983

6 0
4 years ago
Read 2 more answers
Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1
Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

f(x) = x^3+6x-5

For x = 0. the value of the expression is:

f(0) = 0^3+0-5\\f(0) = -5

For x = 1, the value of the expression is:

f(1) = 1^3+6-5\\f(1)=2

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

6 0
3 years ago
Other questions:
  • 1/2 <img src="https://tex.z-dn.net/?f=%5Csqrt%20%7B128%7D" id="TexFormula1" title="\sqrt {128}" alt="\sqrt {128}" align="absmidd
    6·2 answers
  • The width of a rectangle is the length minus 3 units. The area of the rectangle is 40 units. What is the width, in units, of the
    8·1 answer
  • Solve For x . Show all steps / work !
    7·1 answer
  • Which quadratic function has Vertex (-1,4) and passes through (4,19) <br> HELP
    7·1 answer
  • What is the sum of the measurements of all the angles in a polygon with k sides?
    11·1 answer
  • 2(b + v) = X<br> solve for b
    5·1 answer
  • Vaughn spent 3.5 hours at the pool over the past week. If he spent an equal amount of time over the last 7 days, how much time d
    12·2 answers
  • Hellllppppppppppp!!!! Please
    5·1 answer
  • 363 · 62 . 46-4<br> Plsss help solve it :)
    14·1 answer
  • WILL MAKE BRAINLYEST
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!