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2 years ago

Solve For x . Show all steps / work !

Mathematics

1 answer:

Paraphin [41]2 years ago

5 0

Answer:

x = 46

Step-by-step explanation:

sqrt(3x - 17) + 5 = 16

Subtract the numbers

sqrt(3x - 17) = 11

Square both sides

3x - 17 = 121

Solve the linear equation

x = 46

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A water balloon is thrown out of a window 96 feet above the ground. The balloon is traveling downward at 16 feet per second init

gulaghasi [49]

It hits the ground at h=0

0=-16t^2-16t+96
undistribute -16
0=-16(t^2+t-6)
factor
0=-16(t-2)(t+3)
set to zero
0=t-2
2=t

t+3=0
t=-3, nope, we can't have negative time

at t=2, or 2 seconds

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3 years ago

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sukhopar [10]

Answer:

Step-by-step explanation:

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2 years ago

The train to Boston traveled at an average speed of 50 miles per hour for 5 hours. The train to Hartford traveled at an average

lawyer [7]

To find how many miles per hour you need to divide 50 by 5 to get the number of miles per hour and do the same thing to the 2nd step and to find the difference you need to subtract the numbers. Hope it helps!!!

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3 years ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.