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Leni [432]
4 years ago
12

Miller has a painting that is 4 ft by 8 ft. What will the dimensions of the painting be if he scales it down by a factor of one-

fourth ?
A.) 4 ft by 8 ft
B.) 2 ft by 4 ft
C.) 1 ft by 2 ft
D.) 16 ft by 32 ft
Mathematics
2 answers:
natta225 [31]4 years ago
8 0
The answer is C) 1 ft by 2 ft
You can take 4*0.25 and 8*0.25
You end up with 1 by 2
Artemon [7]4 years ago
4 0

Answer:

Have a wonderful day!

Hope this helped!

My name is, Lincoln

The answer is C) 1 ft by 2 ft

You can take 4*0.25 and 8*0.25

You end up with 1 by 2

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The sum for 6,498.123
12345 [234]

Total numbers: 2

Sum of numbers: 504.123

3 0
4 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
4 years ago
Cos (90°- x) = -0.7. What is sin x?
Olegator [25]
<span>Cos (90°- x)=-0.7
as</span><span>Cos (90°- x)=sinx
so sinx =-0.7</span>
5 0
4 years ago
Heather's puppy weighs 23 pounds. He has been gaining (3 pounds every month as he grows. If this pattern continues, how much wil
disa [49]
It will be 5x3=15+23=38 so 38 pounds the puppy weigh
3 0
3 years ago
Read 2 more answers
Han's bank account has a balance that is overdrawn and his account balance is -$13.00. How much would he need to deposit in orde
Alisiya [41]

Answer:

$23.00

Step-by-step explanation:

Formula: -13 + d = 10 (d = deposit)

To get d by itself, add 13 to 10: d = 23

Therefore, you need to deposit $23.00.

4 0
3 years ago
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