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LiRa [457]
3 years ago
7

Which expression is equivalent to (x^4/3 x^2/3)^1/3?

Mathematics
2 answers:
Georgia [21]3 years ago
7 0
The answer is B, x^2/3
forsale [732]3 years ago
7 0

Answer : The correct option is, x^{\frac{2}{3}}

Step-by-step explanation :

The given expression is :

(x^{\frac{4}{3}}\times x^{\frac{2}{3}})^{\frac{1}{3}}

First we have to solve the term present in the bracket.

Identity used : x^a\times x^b=x^{(a+b)}

\Rightarrow (x^{(\frac{4}{3}+\frac{2}{3})})^{\frac{1}{3}}

By the adding the powers of 'x', we get:

\Rightarrow (x^{\frac{6}{3}})^{\frac{1}{3}}

\Rightarrow (x^{2})^{\frac{1}{3}}

Now we have to use identity (x^{a})^b=x^{ab}, we get :

\Rightarrow (x)^{(2\times \frac{1}{3})}

\Rightarrow (x)^{\frac{2}{3}}

Therefore, the correct option is, x^{\frac{2}{3}}

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suppose Tomas buys a total of 30 baseball and football cards in week 5 . how many of each would he have to buy to keep the same
Charra [1.4K]

Answer:

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Step-by-step explanation:

The only relationship shown in the table is in week 1, where the ratio of baseball to football cards is ...

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In week 1, the total of these numbers is 15. You want the total in week 5 to be 30, double the total in week 1. So, Thomas needs to purchase double the numbers he purchased in week 1:

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_____

<em>Comment on the attachment</em>

This table came from another question you posted, a question with no content other than the table. The blue numbers are blanks in the original table that have been filled in so as to keep the same 3:2 proportion in each week. They appear to have no bearing on this question.

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1234567891011121314151617181920
Debora [2.8K]

Answer:

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Step-by-step explanation:

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