Answer:
0.095
Explanation:
Phenylkentonuria is a disease caused by a recessive allele.
The frequency of the recessive allele + the frequency of the dominant allele equals 1.
The frequency of the recessive allele is q = 0.05
The frequency of the dominant allele then is p = 1 - q = 0.95
If people mate randomly, the frequency of the homozygous dominant genotype will be p², the frequency of the heterozygous genotype will be 2pq and the frequency of the homozygous recessive genotype will be q² .
2pq=2× 0.05 × 0.95
2pq=0.095
The heterozygote frequency in the population is 0.095
Answer:
None
Explanation:
The desired homozygous dominant genotype is AABBCCDDEE. To have an offspring with genotype "AABBCCDDEE", at least one copy of the dominant alleles for the genetic loci should be present in either of the parent. However, both the parents are homozygous recessive for all the five mentioned genetic loci and therefore, cannot have a progeny with homozygous dominant genotype "AABBCCDDEE". All the progeny of a cross between the two parents each with genotype "aabbccddee" would have homozygous recessive for all the give loci.
aabbccddee x aabbccddee = All aabbccddee
Answer:
mitochondria
Explanation:
In aerobic glycolysis: NADH is transferred into mitochondria via the mitochondrial shuttle, where it is oxidized to NAD in the respiratory chain, ultimately producing ATP.
