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3 years ago

Please help ASAP!!!!!!!!!!

Mathematics

1 answer:

zepelin [54]3 years ago

4 0

Answer:

(c-a, 0)

Step-by-step explanation:

The horizontal space between (c, b) and P is the same as the space between (a, b) and O.

Coordinates are written (x, y), where x is for horizontal space.

P is on the x-axis, making the y-coordinate 0.

(a+c, 0) would be to the right of the entire parallelogram.

(c, 0) would be directly below (c, b).

(a-c, 0) would be to the left of the entire parallelogram and in the other quadrant.

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Find the area for both. The TRIANGLE looking one is the first one!!

Rudiy27

The first one is b the second one is b too

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4 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

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$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

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3 years ago

when multiplie discount are used if an item is first discount by 40%,then again by 30%.then again by 10%,the final or cumulative

nadezda [96]

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3 years ago

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Step-by-step explanation:

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Answer:

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