If Lu bought 7.25 pounds of rice for 4.75 about how much did he pay per pound

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

4 0

3 years ago

The half-life of a certain radioactive material is 83 hours. An initial amount of the material has a mass of 67 kg. Write an exp

Anvisha [2.4K]

Answer:

Initial amount of the material is 67 kg
Hal-life is 83 hours

The required equation is:

m(x) = 67 * $(1/2)^{x/83}$ , where m- remaining amount of the radioactive material, x - number of hours

After 5 hours the material remains:

m(5) = 67 * $(1/2)^{5/83}$ = 64.260 (rounded)

4 0

3 years ago

The dot plots below show the runs scored in each of the first games of the season by the Hawks and the Eagles. Runs Scored (Ha R

omeli [17]

Answer:

Part B: 8 and 2 (more answers ofc)

Part C: Two more dots on 6 (more than one answer tho)

Step-by-step explanation:

Part B:

The added number of dots is 39 at the beginning and the mean is 3.9. (39/10). Since we have to add 2 dots the equation will be (39 + ? + ?) / 12 = Less than 3.9. We also need the range to increase. This means that one of the blanks must be larger than 7 (the largest dot on the dot plot!) I just went with 8 to keep the mean as small as possible. This leaves 1 more blank to figure out. There are multiple answers to this problem but I went with 2 just because then the mean would be 3.5 a better answer than something like 3.58333333333.

Part C:

If you think about it all the dots added up should be 6x12 = 72. Currently all the dots add up to 60. 72-60 is 12. This means that 12 is equal to 2 dots. I guess you could also do 5 and 7, 8 and 4, etc.

G'day

-birb

4 0

2 years ago

The amount of money A accrued at the end of

Rudiy27

B is the answer no capppppp

7 0

3 years ago

What is the solution to the inequality 28 > 4 – 2p?

Schach [20]

Answer:

-12 < p

Step-by-step explanation:

28 > 4 – 2p

Subtract 4 from each side

28-4 > 4-4 – 2p

24 > -2p

Divide each side by -2, remembering to flip the inequality

24/-2 < -2p/-2

-12 < p

4 0

3 years ago