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Mandarinka [93]
3 years ago
7

I need help on 7b. I don’t know where to start?

Mathematics
1 answer:
Gwar [14]3 years ago
8 0

Answer:

all work is shown and set

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Mason has a collection of .49 stamps, .20 stamps and .3 stamps worth 23.55. He has 56 total .49 and .20 stamps and the number of
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Answer: Mason has 40 forty-nine cent stamps, 16 twenty cent stamps and 25 three cent stamps

Step-by-step explanation:

Let x represent the number of 49 cent stamps that Mason has.

Let y represent the number of 20 cent stamps that Mason has.

Let z represent the number of 3 cent stamps that Mason has.

Mason has a collection of 49 cent stamps, 20 cent stamps, and 3 cent stamps worth $23.55. This means that

0.49x + 0.2y + 0.03z = 23.55 - - - - -1

He had 56 total 49 cent and 20 cent stamps. This means that

x + y = 56

x = 56 - y

The number of 3 cent stamps is nine more than the number of 20 cent stamps. This means that

z = y + 9

Substituting x = 56 - y and z = y + 9 into equation 1, it becomes

0.49(56 - y) + 0.2y + 0.03(y + 9) = 23.55

27.44 - 0.49y + 0.2y + 0.03y + 0.27 = 23.55

27.44 + 0.27 - 0.49y + 0.2y + 0.03y = 23.44

27.71 - 0.26y = 23.55

- 0.26y = 23.55 - 27.71

- 0.26y = - 4.16

y = - 4.16/ - 0.26y

y = 16

x = 56 - y = 56 - 16

x = 40

z = y + 9 = 16 + 9

z = 25

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Answer:

Answer is D.

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Step-by-step explanation:

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(BRAINLIEST!!) Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
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Step-by-step explanation:

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Answer:

C. The triangles are not similar.

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Divide the short sides and long sides to see if they are similar:

24/16 = 1.5

36/28 = 1.29

The triangles are not similar.

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