Answer:
Kindly check explanation
Step-by-step explanation:
Given the details :
Kofi is older than kweku
kofi's age = (5x-4) years
kweku's age = (2x+1) years
a. write down an expression, interns of x,for how much old is Kofi than kweku
Equate the ages of Kofi and kweku
(5x - 4) = (2x + 1)
5x - 4 = 2x + 1
5x - 2x = 1 + 4
3x = 5
3x - 5
B.) if Kofi is tens years older than kweku, find the value of x and the ages of Kofi and kweku
Then,
(5x-4) = (2x + 1) + 10
5x - 4 = 2x + 1 + 10
5x - 2x = 1 + 10 + 4
3x = 15
x = 5
Kofi's age : 5x - 4
5(5) - 4 = 25 - 4 = 21 years
Kweku's age : (2x + 1)
2(5) + 1 = 10 + 1 = 11 years
Pretty difficult problem, but that’s why I’m here.
First we need to identify what we’re looking for, which is t. So now plug 450k into equation and solve for t.
450000 = 250000e^0.013t
Now to solve this, we need to remember this rule: if you take natural log of e you can remove x from exponent. And natural log of e is 1.
Basically ln(e^x) = xln(e) = 1*x
So knowing this first we need to isolate e
450000/250000 = e^0.013t
1.8 = e^0.013t
Now take natural log of both
Ln(1.8) = ln(e^0.013t)
Ln(1.8) = 0.013t*ln(e)
Ln(1.8) = 0.013t * 1
Now solve for t
Ln(1.8)/0.013 = t
T= 45.21435 years
Now just to check our work plug that into original equation which we get:
449999.94 which is basically 500k (just with an error caused by lack of decimals)
So our final solution will be in the 45th year after about 2 and a half months it will reach 450k people.
