Answer:
![Terms: 3\ and\ x + 2](https://tex.z-dn.net/?f=Terms%3A%203%5C%20and%5C%20x%20%2B%202)
![Product = 3x + 6](https://tex.z-dn.net/?f=Product%20%3D%203x%20%2B%206)
Step-by-step explanation:
See attachment for complete question.
From the attachment, there are 3 columns and 3 rows
The 3 columns represent the first factor
To get the second factor, we have to analyze the 3 rows in the attachment.
Notice that the first row is bigger than the other two rows.
This big row will be represented with variable x
Notice that the boxes in second row are smaller than the first row and the + sign is written on each of the boxes.
This is represented with + 1
Also, notice that the boxes in third row are smaller than the first row and the + sign is written on each of the boxes.
This is also represented with + 1
Hence, the expression for the rows is x + 1 + 1 = x + 2
The product is then calculated as:
![Product = 3 * (x + 2)](https://tex.z-dn.net/?f=Product%20%3D%203%20%2A%20%28x%20%2B%202%29)
![Product = 3 * x + 3*2](https://tex.z-dn.net/?f=Product%20%3D%203%20%2A%20x%20%2B%203%2A2)
![Product = 3x + 6](https://tex.z-dn.net/?f=Product%20%3D%203x%20%2B%206)