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Goryan [66]
3 years ago
11

Students in a class were asked to name their favorite flavor of ice cream. The results are shown in the circle graph. How many t

imes more students prefer cookies and cream than prefer strawberry?
Cookies and Cream: 18%
Strawberry: 2%
Cookie Dough: 35%
Vanilla: 25%
Chocolate Chip: 20%
Mathematics
2 answers:
balu736 [363]3 years ago
6 0
9 Times, hopes this helped
Korvikt [17]3 years ago
3 0

Answer: 9 times

Step-by-step explanation:

Let the total number students be x.

Then the number of students liked cookies and cream = 18% of x= 0.18 x

The number of strawberry = 2% of x = 0.02 x

Clearly, 0.18 x> 0.02 x

The number of times more students prefer cookies and cream than prefer strawberry ==\frac{0.18x}{0.02x}=9

Hence, The students prefer 9 times cookies and cream than prefer strawberry.

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84.7g of sugar is needed to make 11 cakes. How much sugar is needed for 5 cakes
Yuri [45]

Answer:

38.5 grams of sugar for 5 cakes

Step-by-step explanation:

Set up a ratio of grams to cakes

84.7g:11

How much for 1 cake(unit rate because you want sugar over cakes)?

Just divide by 11.

7.7g:1

But you need 5 cakes so multiply by 5

38.5g:5

4 0
3 years ago
Read 2 more answers
F(x)=2x^2-x-10 part a: what are the X intercepts of the graph of f(x)? Show your work
Genrish500 [490]
A. x intercepts are where the graph hits the x axis or where f(x)=0
0=2x^2-x-10
solve
hmm
we can use the ac method
multiply 2 and -10 to get -20
what 2 numbers muliply to get -20 and add to get -1 (the coefint of the x term)
-5 and 4
split the midd into that
0=2x^2+4x-5x-10
group
0=(2x^2+4x)+(-5x-10)
factor
0=2x(x+2)-5(x+2)
undistribute
0=(x+2)(2x-5)
set each to 0
0=x+2
0=-2

0=2x-5
5=2x
5/2=x

x intercepts are at x=-2 and 5/2 or the points (-2,0) and (5/2,0)


B. ok, so for f(x)=ax^2+bx+c
if a>0, then the parabola opens up and the vertex is a minimum
if a<0 then the parabola opens down and the vertex is a max

f(x)=2x^2-x-10
2>0
opoens up
vertex is minimum

ok, the vertex

the x value of  the vertex in f(x)=ax^2+bx+c= is -b/(2a)
the y value of the vertex is f(-b/(2a)) so
given
f(x)=2x^2-x-10
a=2
b=-1
-b/2a=-(-1)/(2*2)=1/4
f(1/4)=2(1/4)^2-(1/4)-10
f(1/4)=2(1/16)-1/4-10
f(1/4)=1/8-1/4-10
f(1/4)=1/8-2/8-80/8
f(1/4)=-81/8
so the vertex is (1/4,-81/8) or (0.25,-10.125)


C. graph the x intercepts and the vertex
the vertex is min and the graph goes through the x intercepts
4 0
3 years ago
Find the radical equivalent of 27^2/3 and compute it.<br> please help i'm taking a test.
AveGali [126]
Note that (a^b)^c=a^(bc) so in this case we have:

(27^(1/3))^2  the cube root of 27=±3

(±3)^2  and ±3^2=9

So the equivalent expression is 9  or if you need an exponent 9^1 :)

I am assuming that you meant 27^(2/3)
6 0
3 years ago
Read 2 more answers
Solve the following equation for h.<br> r+3Q/h=t
Arada [10]

Answer:

             \bold{h=\dfrac{3Q}{t-r}}

Step-by-step explanation:

\bold{r+\frac{3Q}h=t}\\-r\qquad\ -r\\\bold{\frac{3Q}h=t-r}\\\cdot h\qquad \cdot h\\ \bold{3Q=(t-r)h}\\^{\div(t-r)\quad\div(t-r)}\\\bold{\dfrac{3Q}{t-r}=h}

Or, if you mean (r+3Q)/h=t:

\bold{\frac{r+3Q}h=t}\\{}\ \ \cdot h\quad\ \cdot h\\\bold{r+3Q=ht}\\{}\ \ \div t\qquad \div t\\\bold{\dfrac{r+3Q}{t}=h}\\\\\bold{h=\dfrac{r+3Q}{t}}

4 0
3 years ago
Which one does not belong?
avanturin [10]

Answer:

last one - 4/-2

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two minus(-) becomes a plus(+)

8 0
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