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Llana [10]
3 years ago
14

Please tell the LCM of the following -​

Mathematics
2 answers:
Alex17521 [72]3 years ago
6 0

Answer:

Step-by-step explanation:

2) 24 = 2 *2*2*3 = 2³ * 3

54 = 2*3*3*3 = 2 * 3³

LCM = 2³ * 3³ = 8*27 = 216

12) 14 = 2 *7

25 = 5*5 = 5²

LCM = 2*7 * 5² = 14*25 = 350

37) 12  = 2*2*3 = 2² * 3

     32 = 2*2*2*2*2 =2^5

LCM = 2^5 * 3 = 32*3 = 96

LCM -> common number with highest power and the rest all numbers

Arada [10]3 years ago
4 0

Answer:

Below.

Step-by-step explanation:

I won't do all of these for you but I'll show you the general method.

First write each number  as prime factors.

For example number 7:

LCM of 24 and 34.

24 = 2 * 2 * 2 * 3

34 = 2 * 17

The LCM  is the multiple of all these factors EXCEPT if there is a duplicate number you only use it once.

There is one duplicate here - the 2 ( in bold) so we only use  this once.

So the LCM = 2 * 2 * 2 * 3 * 17 = 408.

Number 1:

13, 25

13 = 13

25 = 5 * 5

There are no duplicates  so the LCM = 13 * 5 * 5 = 325.

Number  18:

15, 84

15 = 3 * 5

84 = 2 * 2 * 3 * 7

Number 3 is common to both sets so it is only used once:

LCM = 2 * 2 * 3 * 5 * 7 = 420.

Number 40:

18, 48

18 = 2 * 3 * 3

48 = 2 * 2 * 2 * 2 * 3

There are 2 sets of duplicates here, 2 and 3 .

LCM =  2 * 2 * 2* 2 * 3 * 3 = 144.

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x=18

Step-by-step explanation:

Hey There!

So if you did not know all of the angles in a triangle will add up to equal 180

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Which equation demonstrates the additive identity property?
Mrrafil [7]

Answer:

Step-by-step explanation:

Solve for o in the equation (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 41o(7 + 4)(1) = 7 + 41o(7 + 41) + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 41o(7 + 4): Distribute the 41o to each term in (7+4)

41o * 7 = (41 * 7)o = 287o 41o * 4 = (41 * 4)o = 164o

Our Total expanded term is 287o + 164o

Simplify 41o(7 + 41): Distribute the 41o to each term in (7+41)

41o * 7 = (41 * 7)o = 287o 41o * 41 = (41 * 41)o = 1681o

Our Total expanded term is 287o + 1681o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 164o(1): Distribute the 164o to each term in (1)

164o * 1 = (164 * 1)o = 164o Our Total expanded term is 164o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o = 7 + 287o + 1681o + ( - 7 - 41) = 0

Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

Step 2: Cancel 14©(7 on the right side: 0o = 0 Step 3: Divide each side of the equation by 0

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