Answer:
148
Explanation:
According to Hardy-Weinberg equilibrium,
p + q = 1
p² + 2pq + q² = 1 where,
p = frequency of dominant allele
q = frequency of recessive allele
p² = frequency of homozygous dominant genotype
2pq = frequency of heterozygous genotype
q² = frequency of homozygous recessive genotype
Here,
Total population = 592
Number of NN people = 148
Frequency of N blood group or NN genotype (q²) = 148/592 = 0.25
q = √0.25 = 0.5
p = 1 - q
= 1 - 0.5 = 0.5
Hence, p = 0.5
Frequency of MM genotype = p² = 0.25
Number of people with MM genotype = 0.25*592 = 148
Hence, 148 people will have MM genotype or M blood group.
-Plant cells are more rigid due to the cell wall.
As
we know our blood has four main components which are plasma, red
blood cells, white blood cells and platelets. That is why a
hemophiliac must receive regular injections of platelets to stay
alive. This is done by injecting into their bloodstream human plasma
which contains many proteins, glucose, clotting factors,
electrolytes, hormones, and carbon dioxide.
<span>I
hope it helps, Regards.</span>
S stand for 'synthesis' or 'to make' - the S phase is a phase dedicated to synthesizing material in preparation for division - for example, DNA is doubled during the S phase.
Complete question:
A sample of butterflies contained 50% yellow-winged individuals and 50% black-winged individuals. In this species, wing color is determined by a single gene with two alleles, and the allele for black is dominant. Which of the following statements about the allele frequencies in the sample would most likely be true? Do not assume that this sample was obtained from a population in genetic equilibrium.
a)The frequency of the yellow allele is greater than that of the black allele.
b)The allele frequency of yellow is 3 times the allele frequency of black.
c)The allele frequency of yellow is twice the allele frequency of black.
d)The allele frequencies of black and yellow are equal.
e) The allele frequency of black is greater than the allele frequency of yellow.
2.Now assume that the population of butterflies sampled in question above is in Hardy-Weinberg equilibrium. Also assume that the sample is random and large enough that the allele frequencies in the sample equal the allele frequencies in the population. What is the frequency of the allele for a) yellow wings in the population? Assuming Hardy-Weinberg equilibrium in question 1, what would the correct answer be and why?
Answer:
- a)The frequency of the yellow allele is greater than that of the black allele.
- f(b) = q = 0.71
Explanation:
Due to technical problems, you will find the complete explanation in the attached files
