Answer:
1/4y
Step-by-step explanation:
(-x^-1)^0/(4y^-1*y^2)
anything to the power of 0 gives you 1,
1/(4y^-1*y^2)
-1+2=1
1/4y^1=1/4y
Answer:11
Step-by-step explanation:
First multiply 4 and 2.
Which makes the equation 3+8
Which makes your answer 11
The answer would be (A) <span>(x − 4)^2 + (y − 4)^2 = 16
</span>
Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
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