Answer:
x = 0 and y = 3
Step-by-step explanation:
Using elimination method, we can solve for x and y in the simultaneous equation
y = 2x + 3 .................................eqn 1
y = -3x + 3 .................................eqn 2
multiply equation 1 by 3 and equation 2 by 2, then we will have
(y = 2x + 3) × 3
(y = -3x + 3) × 2
3y = 6x + 9 ...............................eqn 3
2y = -6x + 6 ................................eqn 4
Add eqn 3 and 4 together and we will eliminate x and have
5y = 15
Divide both sides by 5, and we will have
y = 3
To solve for x, substitute 3 for y in eqn 1
y = 2x + 3
3 = 2x + 3
collect like terms
3 - 3 = 2x
0 = 2x
Therefore x = 0
It’s the second one , im pretty sure .
the correct answer is actually {1, 5, 8, 12, 17}
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Answer:
Multiply 2/3 and your number. If you have a whole number, convert it to a fraction by putting it over a denominator of 1. When multiplying fractions, calculate numerator times numerator, then denominator times denominator. For example, to find two-thirds of 18, multiply 2/3 x 18/1 to get 36/3.
