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baherus [9]
4 years ago
11

Suppose that the number of bacteria in a certain population increases according to an exponential growth model. A sample of 2600

bacteria selected from this population reached the size of 2873 bacteria in two and a half hours. Find the continuous growth rate per hour. Write your answer as a percentage. Do not round any intermediate computations, and round your percentage to the nearest hundredth.
Mathematics
1 answer:
melisa1 [442]4 years ago
3 0

Answer: There is 3.994% continuous growth rate per hour.

Step-by-step explanation:

Since we have given that

Initial bacteria = 2600

After two and a half hours,

Number of bacteria = 2873

We need to find the continuous growth rate per hour.

As we know the equation for continuous growth rate per hour.

y=y_0e^{rt}\\\\2873=2600e^{2.5r}\\\\\dfrac{2873}{2600}=e^{2.5r}\\\\1.105=e^{2.5r}\\\\\text{Taking log on both the sides}\\\\\ln 1.105=2.5r\\\\0.0998=2.5r\\\\r=\dfac{0.0998}{2.5}\\\\r=0.0399\times 100\\\\r=3.994\%

Hence, there is 3.994% continuous growth rate per hour.

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3 years ago
Fern knitted 20 scarves over 5 nights. After 8 nights of knitting, how many scarves would fern have made in total.
Studentka2010 [4]

Answer:

Fern will knit 32 scarves in 8 nights.

Step-by-step explanation:

Number of scarves knitted by Fern in 5 night = 20

Relation between number of scarves knitted and number of nights is proportional,

Therefore, Number of scarves knitted (s) ∝ Number of nights spent to knit the scarves (n)

s ∝ n

s = kn

k = \frac{s}{n}

Here, k = proportionality constant

For s = 20 and n = 5,

k = \frac{20}{5}

k = 4 scarves per night

For 8 nights, by using the same proportionality rule,

k = \frac{s}{8}

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Therefore, Fern will knit 32 scarves in 8 nights.

4 0
3 years ago
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boyakko [2]

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5 0
3 years ago
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4 0
3 years ago
A first number plus twice a second number is 14. Twice the first number plus the second totals 10. Find the numbers.
Nookie1986 [14]

Answer:

first number(x) = 2 second number(y)= 6

Step-by-step explanation:

This is an example of a simultaneous equation.

First write this word problem as equations, where x is the "first number" that you've mentioned and y is the "second number".

x + 2y = 14  (equation 1)

2x + y = 10  (equation 2)

This is solved using the elimination method.

We need to make one of the coefficients the same - in this case we can make y the same. In order to do this we need to multiply equation 2 by 2, so that y becomes 2y.

2x + y = 10 MULTIPLY BY 2

4x + 2y = 20 (this is now our new equation 2 with the same y coefficient)

Now subtract equation 1 from equation 2.

4x - x + 2y - 2y = 20 - 14  (2y cancels out here)

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x = 2

Now we substitute our x value into equation 1 to find the value of y.

2 + 2y = 14

2y = 12

y = 6

Hope this has answered your question.

6 0
3 years ago
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