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jok3333 [9.3K]
3 years ago
14

Solve: 92x + 1 = 93x – 2

Mathematics
2 answers:
vichka [17]3 years ago
6 0

Answer:

x equals 3 :) if i helped, please give brainliest!

Step-by-step explanation:

Scrat [10]3 years ago
5 0

Answer:

x=3

The follow up is C.

Good luck!!

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Help on Math please and thank you
Keith_Richards [23]

Answer:

the value of x to the nearest tenth is 12 * x

5 0
2 years ago
N x 50 = 5,000. Explain your solution
prohojiy [21]
In order to figure out what N is you have to isolate it by dividing by 50 on both sides as shown below:
N*50=5000\\\frac{n*50}{50}=\frac{5000}{50}\\n=100
3 0
3 years ago
3(4a + 2) = 2(a - 2)?
Likurg_2 [28]

Answer:

A= -1

Step-by-step explanation:

8 0
3 years ago
The regular nonagon has rotational symmetry of which angle measures? Check all that apply.
11111nata11111 [884]
Consider the center of the nonagon. If we join the center to all the vertices, the central angle of 360°, is divided into 9 equal angles, each with a measure of:

360°/9=40°

So to a nonagon rotated 40°, clockwise or counterclockwise, is indistinguishable from the original one. 

similarly if we rotate 80 ° c.wise or c.c.wise 

in general, a nonagon has a rotational symmetry of 40°n,

where n∈{...-3, -2, -1, 0, 1, 2, 3}...

where 40°n, for n negative, means we are rotating clockwise.


Answer: any angle which is a multiple of 40°

8 0
3 years ago
Read 2 more answers
If you start with 85 milligrams of Chromium 51, used to track red blood cells, which
zysi [14]

About 92 days are taken for 90 % of the material to <em>decay</em>.

The mass of radioisotopes (m), measured in milligrams, decreases exponentially in time (t), measured in days. The model that represents such decrease is described below:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

  • m_{o} - Initial mass, in milligrams.
  • m(t) - Current mass, in milligrams.
  • \tau - Time constant, in days.

In addition, the time constant is defined in terms of half-life (t_{1/2}), in days:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m_{o} = 85\,mg, t_{1/2} = 27.7\,d and m(t) = 8.5\,mg, then the time required for decaying is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{27.7\,d}{\ln 2}

\tau \approx 39.963\,d

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}

t\approx 92.018\,d

About 92 days are taken for 90 % of the material to <em>decay</em>.

We kindly invite to check this question on half-life: brainly.com/question/24710827

8 0
2 years ago
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