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LiRa [457]
2 years ago
12

What is the solution? pls help

Mathematics
1 answer:
loris [4]2 years ago
3 0

Answer:

Solve by substitution

[y=5/2x-4]

[y= -x+3]

Substitute y = -x +3

[-x+3=5/2x-4]

Isolate x for -x+3=5/2x-4: x=2

For y = -x+3

Substitute x = 2

y= -2+3

Simplify

y=1

The solutions to the system of equations are:

y=1 x=2

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Step-by-step explanation:

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1. Explain the process for combining like terms for 12x - 3y + 8 - 5x + 4y
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Answer: 7x+y+8

Step-by-step explanation:

Combining like terms is just like what it sounds. You take the like terms, or terms that have the same variables and such, and add them together.

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We can see that -3y and 4y are like terms because they both have a numerical coefficient and y for variable.

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In the function y=5x^2-2, what effect does the number 5 have on the graph, as compared to the graph of y=x^2?
allochka39001 [22]

General Idea:

The Rules for Transformations of Functions are given below:

If f(x) is the original function, a > 0 and c > 0; Then

f(x)+k \; \; shift \; f(x) \; UPWARD \; k \; units\\\\f(x)-k \; \; shift \; f(x) \; DOWNWARD \; k \; units\\\\f(x+h) \; \; shift \; f(x) \; LEFT \; h \; units\\\\f(x-h) \; \; shift \; f(x) \; RIGHT \; h \; units\\\\-f(x) \; \; REFLECT \; f(x) \; in \; the \; x-axis\\\\f(-x) \; REFLECT \; f(x) \; in \; the \; y-axis\\\\a \cdot f(x), \; a>1 \; STRETCH \; f(x) \; vertically \; by \; a \; factor \; of \; a\\\\a \cdot f(x), \; 0

f(ax), \; a>1 \; SHRINK \; f(x) \; horizontally \; by \; a \; factor \; of \;\frac{1}{a}  .\\\\f(ax), \; 0

Applying the concept:

In the function y=5x^2-2, the effect that the number 5 have on the graph, as compared to the graph of y=x^2 is given below:

C.it stretches the graph vertically by a factor of 5

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