Let the distance of Judy from intersection is x and distance of Jackie from intersection is y.
We convert the given information to equations, step by step.
Point 1: When Jackie is 1 mile farther from the intersection than Judy.
This means y is 1 mile more than x.
So,
y = 1 + x
Point 2: The distance between them is 2 miles more than Judy’s distance from the intersection.
Distance between is x+ y.
So, x+y is 2 miles more than y.
x+y = y + 2
⇒
x = 2
From point 1 we have:
y = 1 + x = 1+ 2 = 3
So,
Distance of Judy from intersection is 2 miles and distance of Jackie from intersection is 3 miles.
Answer:
4
Step-by-step explanation:
Pythagorean Theorem
a^2+b^2=c^2
C is the hyptonuse A and B are legs.
a^2+3^2=5^2
a^2+9=25
a^2=16
a= sqrt16
a=4
Hope this helps!
Answer:
y = -1x -3
Step-by-step explanation:
