Question

Find the value of x in the isosceles triangle shown below. 2 2 5 8

Answer 1

Answer:

$\sqrt{41}$

Step-by-step explanation:

think of this triangle being made up of 2 triangles with the lengths of 5, 4, and x.

x being the hypotenuse, 5 being one of the legs, and 4 being one of the legs. (8/2).

pythagorean theorem:

a^2 + b^2 = c^2

5^2 + 4^2 = x^2

25 + 16 = x^2

41 = x^2

x = sqrt 41