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Komok [63]
3 years ago
7

Help me.. ASAP just number 10 pls

Mathematics
2 answers:
sergey [27]3 years ago
6 0

10 ~ Spinning A 3

I hope this helps!~ I tried

bazaltina [42]3 years ago
4 0

Honestly I feel like it is 10.

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Find the domain and range of the equation:<br><br>b(x)=|x-3|​
zzz [600]

Domain: Set of all real numbers.

The domain in interval notation is (-infinity, infinity)

The reason why the domain is the set of all real numbers is because we can pick any number we want for x, without having to worry about division by zero errors or taking the square root of negative values. There are no restrictions for x.

==========================================================

Range: Set of all non-negative numbers.

As an inequality, you would write y \ge 0 (y is greater than or equal to 0)

In interval notation, the range is written as [0, infinity)

The absolute value result cannot be negative. The smallest y = |x| can get is y = 0. This applies to y = |x-3| as well. The use of square brackets tells the reader "include y = 0 as part of the range". You always use curved parenthesis for infinity because you can never actually reach infinity.

4 0
4 years ago
Find the length of the hypotenuse. Round your answer to the nearest hundredth. *
Rom4ik [11]

Answer:

c = 8.06

Step-by-step explanation:

Use the Pythagorean theorem.

a^2 + b^2 = c^2

c^2 = a^2 + b^2

c^2 = 4^2 + 7^2

c^2 = 16 + 49

c^2 = 65

c = sqrt(65)

c = 8.06

3 0
3 years ago
I’m hella confused????
Alexeev081 [22]

Answer:

same but use photomath its good

8 0
3 years ago
Hey:) can you please help me posted picture of question
mr Goodwill [35]
The top row contains the product of x^{2} with each term of the expressions x^{6}+ x^{4}+ x^{2} and bottom row contains the product of -1 with each term of expression x^{6}+ x^{4}+ x^{2} .

The final result will be the sum of terms of both rows as shown below:

( x^{6}+ x^{4} + x^{2} )( x^{2} -1) \\  \\ &#10;= x^{2} ( x^{6}+ x^{4} + x^{2} )-1( x^{6}+ x^{4} + x^{2} ) \\  \\ &#10;= x^{8}+ x^{6}+ x^{4}- x^{6}- x^{4}- x^{2}  \\  \\ &#10;= x^{8}- x^{2}

So the correct answer is option D
8 0
3 years ago
General douglas MacArthur, one of the leading generals in World War II was born in 1880 and died in 1964 how old was he when he
malfutka [58]

Answer: he was 84 years old when he died and the fractional part of a century that he live is 21/25

Step-by-step explanation:

General Douglas MacArthur, one of the leading generals in World War II was born in 1880. He died in 1964. The number of years that he lived would be the year he died - the yea he was born. Therefore,

His age when he died

= 1964 - 1880 = 84 years.

The number of years in a century is 100. Therefore, the fractional part of a century that he lived would be

84/100 = 21/25

4 0
4 years ago
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