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Komok [63]
3 years ago
7

Help me.. ASAP just number 10 pls

Mathematics
2 answers:
sergey [27]3 years ago
6 0

10 ~ Spinning A 3

I hope this helps!~ I tried

bazaltina [42]3 years ago
4 0

Honestly I feel like it is 10.

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An auto transport truck holds 12 cars. A car dealer plans to bring in 1,006 new cars in June and July. If an auto transport truc
marin [14]
To find the number of full trucks we can do 1006 / 12. This gives us 83.8333. That is, 83 full trucks and a bit left over.
The bit left over is the answer to the second part, the last truck. 0.8333 is the same as 10/12, so the last truck will have 10 cars in it. If we didn’t know that fraction, we could find the answer by saying 12x83 = 996. 1006 - 996 = 10.

So the final answer is: 83 full trucks and 10 cars in the last truck.
3 0
2 years ago
What is 6÷2(2+1)? explain how did you get the answer
denis-greek [22]

Answer:

6 \div 2(2 + 1) \\ 6 \div 2(3) \\ 3 \times 3 \\  = 9

8 0
3 years ago
Read 2 more answers
Why does insurance often provide "peace of mind"?
snow_tiger [21]
If an item you own is damaged or stolen, insurance will give you money to replace it.
6 0
3 years ago
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CAN ANYBODY PLS HELP
Firdavs [7]

The correct options are

5x =  - 58 \:5x + 4 =  - 54

<h3>How to find same value of x?</h3>

given that

\frac{5}{6} x +  \frac{2}{3}  =  - 9

first find value of x to obtain the equations have the same value of x.

Find the L.C.M between the 6,3

\frac{5x + 4}{6}  =  - 9

Then Cross multiplication should be done

5x + 4 =  - 9 \times 6 \\ 5x + 4 =  - 54 \\ 5x =  - 54 - 4

5x =  - 58

Hence the correct options are

5x =  - 58

5x + 4 =  - 54

Learn more about problems on equations, refer:

https://brainly.in/question/742266

#SPJ9

7 0
1 year ago
Integrate [0, 1/2] xcos(pi*x).
elena-14-01-66 [18.8K]
To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
 and v=intgral cos (xpi)dx
        v=(1/pi)sin(pi*x)
 integration by parts
uv-itgral[0,1/2]vdu just plug ins
 (1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
 =(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
3 0
3 years ago
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