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ahrayia [7]
3 years ago
13

Use the graph of f(x) below, g(x) = 5x + 5, and the table of h(x).

Mathematics
1 answer:
Yakvenalex [24]3 years ago
8 0
The final answer is B
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A tangent line and its normal line have a point of tangency to the function f(x) at (x,y). If the slop of the normal line is m=(
alekssr [168]

Answer:

\displaystyle \\\left(\frac{49}{900},\frac{3761}{900}\right) or approximately (0.544, 4.179)

Step-by-step explanation:

A function and its tangent lines intersect when their slopes are the same. Find the x-coordinate when the slope of f(x) is equal to 8/7 by taking the derivative of f(x):

\displaystyle\\f(x)=\sqrt{x}-x+4\\f'(x)=\frac{1}{2}\cdot\frac{1}{\sqrt{x}}-1=\frac{1}{2\sqrt{x}}-1

Set f'(x) equal to 8/7 and solve for x:

\displaystyle \\\frac{1}{2\sqrt{x}}-1=\frac{8}{7},\\x=\frac{49}{900}

Therefore, f(x) will intersect at a point of tangency with a line of slope 8/7 at x=49/900. Plug in x=49/900 into f(x) to get the y-coordinate:

\displaystyle\\y=\sqrt{x}-x+4 \vert_{x=49/900}=\frac{3761}{900}

⇒Answer: (49/900, 3761/900) or approximately (0.544, 4.179)

5 0
3 years ago
What is 1/7 divided by ? = 14
user100 [1]
First you multiply the numbers you do have to get the number your looking for 1/7•14=2 and 2divided by 1/7=14 so 2 would be your answer
4 0
3 years ago
What is true about the function graphed below?
Dafna1 [17]

Answer:

  D. The axis of symmetry is the y-axis.

Step-by-step explanation:

The vertex is at coordinates (0, 3). Since this parabola opens vertically, its axis of symmetry is the x=coordinate of the vertex: x = 0. That is the equation of the y-axis.

The axis of symmetry is the y-axis.

8 0
3 years ago
Which expression is equivalent to 3xy + 10xy - 5x + 2x - 2yx? A) 15xy + 7x Eliminate B) 13xy - 7x - 2yx C) -8xy D) -3x + 11xy
Vedmedyk [2.9K]

3xy + 10xy - 5x + 2x - 2yx

Add 3xy to 10xy

13xy - 5x + 2x - 2yx

Add -5x to 2x

Final Answer: B.) 13xy -3x - 2yx

3 0
3 years ago
Read 2 more answers
Which table contains the vertex of the graph represented by y=x^2-6x+4?
Vaselesa [24]

vertex = (3,- 5 )

given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then

the x-coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = x² - 6x + 4 is in standard form

with a = 1, b = - 6 and c = 4, hence

x_{vertex} = - \frac{-6}{2} = 3

substitute this value into the equation for y- coordinate

y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5

vertex = (3, - 5 ) → second table




7 0
3 years ago
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