The congruence theorem that can be used is: B. ASA
<h3>What is the ASA Congruence Theorem?</h3>
If we have two triangles that have two pairs of corresponding congruent angles (e.g. ∠LGH ≅ ∠HKJ and ∠LHG ≅ ∠KHJ), and a pair of corresponding congruent sides (e.g. GH ≅ HK), the triangles are said to be congruent triangles by the ASA congruence theorem.
Therefore, triangles GHL and KHL in the image given are congruent triangles by the ASA congruence theorem.
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Answer:
x = 7
42, 35, 7
Step-by-step explanation:
- EG = 5x+7
- EF = 5x
- FG = 2x-7
Point F is on line segment of EG, therefore EG = EF + FG
- 5x + 7 = 5x + 2x - 7
- 2x = 14
- x = 7
Then
- EG = 5*7 + 7 = 42
- EF = 5*7 = 35
- FG = 2*7 - 7 = 7
Answer:
5 x 199
Step-by-step explanation:
You can see that it is divisible by 5, a prime number, because it ends in 5. Once you divide it, you get 199 which itself is a prime number.
Any number from -10 to -∞ would be correct. One example is -79.
Rcsc(theta) = 3
r/sin(theta) = 3
r =3sin(theta)
Now use the relation between polar coordinates and rectangular coordinates
x = rcos(theta)
y = r sin(theta)
=> x = [3sin(theta)]cos(theta)
x = 3 sin(theta)cos(theta)
and y = [3sin(theta)]sin(theta)
y = 3 [sin(theta)]^2
