You look at the triangle...
The sides there are four
The base is the bottom
...
You times 4 by everything inside the parentheses, so the answer would be as follows. 16a + 20b - 12
Okay so this is going to be confusing but work from right to left. since you can’t do 0-5, borrow from the one next to the zero on the top, cross out the one and put zero and add a one on top of the zero which makes it 10. now you can do 10-5 to get 5. put the five down below the line. next solve the second column of numbers ( second to the right). since you cannot do 0- 3, like the last one, you have to borrow from the 7 over to the left. take one from there and cross the seven out and put a six. now you have 10-3 which is 7. put the 7 down. now do move to the next column and do 6-2 to get 4. put the four down below the line. move to the next column and do 2-2 to get 0. put the zero down below the line. lastly, we know the answer has to be negative so we are going to do 2-7 to get -5. put -5 down below the line and together to get the answer -502,275. i know that was very confusing but i hope it helped a little bit. i added a picture to clarify a little
Answer:
<h3>28</h3>
Step-by-step explanation:
Area of a square =
![s^2](https://tex.z-dn.net/?f=s%5E2)
Perimeter =
![4\times s](https://tex.z-dn.net/?f=4%5Ctimes%20s)
Where s = side
Solve for s using the area
![A =49\\\\49 = s^2\\\\Square\:root \:both\:sides\:of\:the\:equation\\\\\sqrt{49} = \sqrt{s^2} \\\\7 =s\\\\s =7](https://tex.z-dn.net/?f=A%20%3D49%5C%5C%5C%5C49%20%3D%20s%5E2%5C%5C%5C%5CSquare%5C%3Aroot%20%5C%3Aboth%5C%3Asides%5C%3Aof%5C%3Athe%5C%3Aequation%5C%5C%5C%5C%5Csqrt%7B49%7D%20%3D%20%5Csqrt%7Bs%5E2%7D%20%5C%5C%5C%5C7%20%3Ds%5C%5C%5C%5Cs%20%3D7)
Find the perimeter
![4\times s\\\\= 4 \times 7\\\\= 28](https://tex.z-dn.net/?f=4%5Ctimes%20s%5C%5C%5C%5C%3D%204%20%5Ctimes%207%5C%5C%5C%5C%3D%2028)