Question

Given: f(x)=x^2 g(x)=x-1 Find f(g(2))+g(f(-1))

Answer 1

Answer:

g(2) = 2 - 1 = 1 \\ f( -1 ) = { - 1}^{2} = 1 \\ f(1) + g(1) = \\ f(1) = {1}^{2} = 1 \\ g(1) = 1 - 1 = 0 \\

$g(2) = 2 - 1 = 1 \\ f( -1 ) = { - 1}^{2} = 1 \\ f(1) + g(1) = \\ f(1) = {1}^{2} = 1 \\ g(1) = 1 - 1 = 0 \\ 1 + 0 = 1$

Answer 2

Answer:

1

Step by step explanation:

$\text{Given that,} ~ f(x) = x^2~ \text{and}~ g(x) = x-1\\\\g(2) = 2-1 = 1\\\\g(f(-1)) = g(1) = 1-1 = 0\\\\f(g(2) + g(f(-1)))= f(1+0) = f(1) = 1^2 =1$