The specific heat of a certain type of cooking oil is 1.75 J/(g⋅°C). How much heat energy is needed to raise the temperature of
1 answer:
Answer:
Explanation:
The formula for the heat transferred to or from an object is
q = mCΔT
Data:
m = 2.94 kg
C = 1.75 J·°C⁻¹g⁻¹
T₁ = 23 °C
T₂ = 191 °C
Calculations:
(a) Convert the mass to grams
m = 2.94 kg = 2940 g
(b) Calculate ΔT
ΔT = T₂ - T₁ = 191 – 23 = 168 °C
(c) Calculate q
q = 2940 × 1.75 × 168 = 864 000 J = 864 kJ
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