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Naily [24]
3 years ago
11

The specific heat of a certain type of cooking oil is 1.75 J/(g⋅°C). How much heat energy is needed to raise the temperature of

2.94 kg of this oil from 23 °C to 191 °C?
Chemistry
1 answer:
crimeas [40]3 years ago
5 0

Answer:

\boxed{\text{864 kJ}}

Explanation:

The formula for the heat transferred to or from an object is

q = mCΔT

Data:

m = 2.94 kg

C = 1.75 J·°C⁻¹g⁻¹

T₁ = 23 °C

T₂ = 191 °C

Calculations:

(a) Convert the mass to grams

m  = 2.94 kg = 2940 g

(b) Calculate ΔT

ΔT = T₂ - T₁ = 191 – 23 = 168 °C

(c) Calculate q

q = 2940 × 1.75 × 168 = 864 000 J = 864 kJ

You must provide\boxed{\textbf{864 kJ}}.

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larisa86 [58]

Answer:

So they have the right answers

Explanation:

I know

7 0
3 years ago
A sample of gas in a balloon has an initial temperature of 20. ∘C and a volume of 1.92×103 L . If the temperature changes to 68
morpeh [17]

Answer:

\boxed{2.23 \times 10^{3} \text{ L}}

Explanation:

The pressure is constant, so we can use Charles' Law.

\dfrac{ V_{1} }{T_{1}} = \dfrac{ V_{2} }{T_{2}}

Data:

V₁ = 1.92 × 10³ L; T₁ = 20 °C  

V₂ = ?;                 T₂ = 68 °C

Calculations:

(a) Convert temperatures to kelvins

T₁ = (20 + 273.15) K = 293.15 K

T₂ = (68 + 273.15) K = 341.15 K

(b) Calculate the volume

\dfrac{ 1.92 \times 10^{3}}{293.15} = \dfrac{ V_{2}}{341.15}\\\\6.550 = \dfrac{ V_{2}}{341.15}\\\\V_{2} = 6.550 \times 341.15 = 2.23 \times 10^{3} \text{ L}

The new volume of the gas is \boxed{2.23 \times 10^{3} \text{ L}}.

6 0
3 years ago
Select all that are true
kipiarov [429]
I think it’s B not quite sure ! Sorry
8 0
3 years ago
A student made the Lewis dot diagram of a compound as shown. Mg is written with two dots shown on its top. Cl is written on the
blsea [12.9K]

Answer:

The dots were not properly located and arrows are not used in Lewis structures

Explanation:

If we intend to write a Lewis structure for a compound, that lewis structure must consist of only dots. These dots actually show the valence electrons on the outermost shell of the molecule.

We do not involve arrows when writing dot electron structures for compounds. The valence electrons of magnesium ought not to be written together because they are not a lone pair, rather they are two unpaired electrons. The use of an arrow suggests a coordinate covalent bond which is not the case here.

The correct lewis structure for MgCl2 is shown in the image attached to this answer.

7 0
3 years ago
What happens if you try to move the atoms very close to each other?
stellarik [79]
They push away from each other or repel due to the same charge they have.
4 0
3 years ago
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