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Naily [24]
3 years ago
11

The specific heat of a certain type of cooking oil is 1.75 J/(g⋅°C). How much heat energy is needed to raise the temperature of

2.94 kg of this oil from 23 °C to 191 °C?
Chemistry
1 answer:
crimeas [40]3 years ago
5 0

Answer:

\boxed{\text{864 kJ}}

Explanation:

The formula for the heat transferred to or from an object is

q = mCΔT

Data:

m = 2.94 kg

C = 1.75 J·°C⁻¹g⁻¹

T₁ = 23 °C

T₂ = 191 °C

Calculations:

(a) Convert the mass to grams

m  = 2.94 kg = 2940 g

(b) Calculate ΔT

ΔT = T₂ - T₁ = 191 – 23 = 168 °C

(c) Calculate q

q = 2940 × 1.75 × 168 = 864 000 J = 864 kJ

You must provide\boxed{\textbf{864 kJ}}.

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Answer:

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proton:

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nuetron:

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hoa [83]

Answer:

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Explanation:

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:

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The direct rule of three is the rule applied in this case where there is a change of units. To perform this conversion of units, you must first know that 1 mL = 1 cubic centimeters. So, if 1 cubic centimeters is 1 mL, how many cubic centimeters equals 250 mL?

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<u><em>The volume in cubic centimeters is 250</em></u>

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3 years ago
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