Write an equation that shows the reaction between acetic acid and triethylamine (CH3CH2)3N. Draw all non-bonding lone electron p
airs and show the electron flow with curved arrows. QUESTION 4 : Which functional groups are in the structure of Prpstaglandin E1 ?
1 answer:
Answer:
-) Acid-base reaction
-) Carboxylic acid, alcohol, alkene and ketone
Explanation:
For the reaction between acetic acid and triethylamine, we will have an <u>acid-base reaction</u>. Therefore a s<u>alt would be produced</u> in this case an <u>"ammonium quaternary salt"</u>. Also, we have to remember that on this reaction the acid is the acetic acid and the base is the triethylamine. See figure 1
For the second question, we have to check the <u>structure of Prostaglandin</u> E1 in which we have the functional groups:
<u>1) Carboxylic acid</u>
<u>2) Alcohol</u>
<u>3) Alkene</u>
<u>4) Ketone</u>
See figure 2.
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Answer:
b. Second order in NO and first order in O₂.
Explanation:
A. The mechanism
B. The rate expressions
The last expression is the rate law for the slow step. However, it contains the intermediate N₂O₂, so it can't be the final answer.
C. Assume the first step is an equilibrium
If the first step is an equilibrium, the rates of the forward and reverse reactions are equal. The equilibrium is only slightly perturbed by the slow leaking away of N₂O₂ to form product.
D. Substitute this concentration into the rate law
The reaction is second order in NO and first order in O₂.