Question

What is the distance, on a coordinate plane, between the points G(2.-3) and D(2, 4)?

Answer 1

Answer:

Therefore ,the distance, on a coordinate plane, between the points G(2.-3) and D(2, 4) is $GD = 7\ units$

Step-by-step explanation:

Given:

point G( x₁ , y₁) ≡ ( 2 ,-3)  

point D( x₂ , y₂) ≡ (2 , 4)  

To Find:

Distance between GD=?

Solution:

Distance Formula between two point is given by

$l(GD) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting the values we get

$l(GD) = \sqrt{((2-2)^{2}+(4-(-3))^{2} )}$

$l(GD) = \sqrt{((0)^{2}+(4+3))^{2} )}=\sqrt{49}=7\\l(GD)=7\ units$

Therefore ,the distance, on a coordinate plane, between the points G(2.-3) and D(2, 4) is $GD = 7\ units$