First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
Answer:
$407.50
Step-by-step explanation:
take 9.75 × 17=165.75
take 9.75 × 25=243.75
add 165.75 and 243.75=407.50
turn into dollars $407.50
Answer:
-4x-6x=-20=
x=2
-3(2x-3)=33=
x=-4
4x+3x+2x=180
x=20
Step-by-step explanation:
-4x-6x=-20
-4+(-6)=-10x
-10x=20 (divide both by 10)
x=-2 (divide by -1 to get positive)
x=2
-3(2x-3)=33
-6x+9=33
-9 . -9
-6x=24 (divide both by -6)
x=-4 (divide by -1 to make positive)
4x+3x+2x=180
(combine like terms)
9x=180 (divide both sides by 9)
x=20
I think C would be for number 11
A is for 12.
x/2 < - 18
