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allochka39001 [22]
4 years ago
13

HELP PLEASE!!

Mathematics
1 answer:
Alja [10]4 years ago
5 0

Answer:

1. y = (1/6)(x +5)^2 -4.5

2. y = (-1/20)(x -10)^2 +1

Step-by-step explanation:

For focus (p, q) and directrix y=r, the equation is ...

y = 1/(2(q-r))·(x -p)^2 +(q+r)/2

___

1. For (p, q) = (-5, -3) and r = -6, the equation is ...

y = 1/(2(-3-(-6))(x -(-5))^2 +(-3-6)/2

y = 1/6(x +5)^2 -4.5

___

2. for (p, q) = (10, -4) and r = 6, the equation is ...

y = 1/(2(-4-6))(x -10)^2 +(-4+6)/2

y = (-1/20)(x -10)^2 +1

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What is the solution to the system of equations? Y=-3-2. 5x+2y=15
ivolga24 [154]

Answer:

x=-19

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Step-by-step explanation:

y=-3x-2.

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substitute y into 5x+2y =15

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distribute

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now lets find y

y= -3x-2

y = -3(-19) -2

y = 57-2

y =55



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