Start at 235 on a number line then go 123 places to the right and land on 358.
Answer:
16 1/3
Step-by-step explanation:
add 7 to 42 to get 49, then divide by 3 to get 16 1/3. :)
Determine the measure of bases a and b and height h of the given trapezoid. Given the coordinates of the points, the distance is calculated through the equation,
d = sqrt ((x₂ - x₁)² + (y₂ - y₁)²)
Base 1: (-2,2) and (1,-2):
d= sqrt ((-2 - 1)² + (2 - -2)²) = 5
Base 2: (2,5) and (11, -7)
d = sqrt ((2 - 11)² + (5 - -7)²) = 15
Height: (-2,2) and (2, 5)
h = sqrt ((-2 -2)² + (2 - 5)²) = 5
The equation for the area of the trapezoid is,
A = (1/2)(base1 + base2)h
Substituting the known values,
A = (1/2)(5 + 15)(5) = 50
ANSWER: 50 square units
Answer:
∠ WZX = 50°
XW is not an altitude.
Step-by-step explanation:
16. See the attached figure.
XW is the angle bisector of ∠ YXZ, hence, ∠ WXY = ∠ WXZ
Now, given that ∠ YXZ = 8x + 34 and ∠ WXY = 10x - 13
Hence, ∠ YXZ = 2 ∠ WXY
⇒ 8x + 34 = 2(10x - 13)
⇒ 8x + 34 = 20x - 26
⇒ 12x = 60
⇒ x = 5.
Hence, ∠ XZY = ∠ WZX = 10x = 50° (Answer)
Now, ∠ WXZ = ∠ WXY = 10x - 13 = 37°
Hence, from Δ WXZ,
∠ WZX + ∠ WXZ + ∠ XWZ = 180°
⇒ 50° + 37° + ∠ XWZ = 180°
⇒ ∠ XWZ = 93° ≠ 90°
Hence, XW is not an altitude. (Answer)
Answer:
2y = x+6
Step-by-step explanation:
From (y-1) = -2(x-1)
y-1 = -2x+2
y=-2x+2+1
y=-2x+3 compare with y = mx +C
m1= -2
For perpendicularity rule: m1m2 = -1
m2 = -1/-2 = 1/2
Equation of the line that passes through (0,3) is
y-y1 = m2(x-x2)
y-3 = 1/2(x-0) = 1/2(x)
y-3 = x/2
Multiply through by 2
2y-6 = x
2y = x+6
2y-x=6
2y-x-6=0
