Answer:
A) 0 , B) 0.0199 , C) 200
Step-by-step explanation:
Let X denotes no. of computers fail on day
X ~ Bin (n = 4 , p = 0.05)
A] P (X = x) = (n c x) p^x q^n-x
P (X = 4) = (4 c 4) (0.005)^4 (0.995)^0
(0.05)^4 ~ 0
B] P (X <u>></u> 1) = 1 - P (X < 1) = 1 - P (X = 0)
1 - { ( 4 c 0) (0.005)^0 (0.995)^ 4 }
1 - (0.995)^ 4 ~ 0.0199
C] Let Y depict mean number of days until a specific computer fails
Y ~ Geom (p = 0.005)
Mean = E (Y) = 1/p = 1/0.05 = 200
Answer:
24.75m ≤ 30m < 35.75m
Step-by-step explanation:
Minimum area:
5.5 (lower bound of 6m) * 4.5 (lower bound of 5m) = 24.75m
Maximum area:
6.5 (upper bound of 6m) * 5.5 (upper bound of 5m) = 35.75m
Normal area:
6*5=30m
I hope that makes some sense or helps a little!
Answer:
Thats facts
Step-by-step explanation:
prove me wrong
7 ×5 = 35 and 5 × 7 = 35
ans is 35
Answer:
-7j-k-1
Step-by-step explanation:
10k + 17 - 7j -18 -11k
10k-11k
-1k
17-18
-1
-7j-k-1