4 years ago

Center 3,6 radius 6, center -2,5 radius 4

Mathematics

1 answer:

morpeh [17]4 years ago

4 0

$(x-3)^2 + (y-6)^2 = 6^2$

$(x+2)^2 + (y-5)^2=4^2$

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What is the sum of the arithmetic sequence 3, 9, 15..., if there are 36 terms?

EastWind [94]

We know that
the formula of the <span>the sum of the arithmetic sequence is
Sum=n*(a1+an)/2

n=36
a1=3
a36=?

find a36
an=a1+(n-1)*d

for n=2 a2=9
9=3+(2-1)*d----> 9=3+d----> d=6
so
for n=36
a36=a1+(36-1)*6----> a36=3+35*6----> a36=213

</span>Sum=n*(a1+an)/2-----> 36*[3+213]/2----> 3888

the answer is
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