Answer:
The general preparation of esters( for example ethyl ethanoate) is through a process known as ESTERIFICATION.
Explanation:
The formation of an ester by the reaction between an alkanol and an acid is known as esterification. This reaction is extremely slow and reversible at room temperature, and is catalyzed by a high concentration of hydrogen ions.
In the preparation of one of the simpler esters known as ETHYL ETHANOATE the reactants include ethanol(an alcohol) and glacial ethanoic acid(a carboxylic acid) in the presence of concentrated tetraoxosulphate VI acid as a CATALYST. Note that, a catalyst is any substance that is able to increase the rate of a chemical reaction.
The mixture is warmed in a water bath( hot but not boiling) for about 25 minutes. The mixture is poured into a beaker partially filled with a sodium or calcium chloride to remove interacted ethanol. The ethyl ETHANOATE floats on the mixture as oily globules.
Answer: The velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.
Explanation:
Given:
= 0.2 kg,
= 0.15 kg
= 2 m/s,
= 0 m/s,
= ?,
= 1.5 m/s
Formula used is as follows.

where,
v = velocity before collision
v' = velocity after collision
Substitute the values into above formula as follows.

Thus, we can conclude that the velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.
Yes thenpropert snd the negative end causes a iconic water fall
<u>Answer:</u> The new pressure for oxygen gas is 6 atm.
<u>Explanation:</u>
To calculate the new pressure of the gas, we use the equation given by Boyle's Law.
This law states that the pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.
Mathematically,

or,

where,
are the initial pressure and volume of the gas.
are the final pressure and volume of the gas.
We are given:

Putting values in above equation, we get:

Hence, the new pressure for oxygen gas is 6 atm.