Answer:
B. adding heat to the system and having the system do work on the surroundings
Explanation:
The internal energy of a system is the energy contained within the system. From first law of thermodynamics we have the equation : dq=du+dw
and we know that energy can neither be created nor destroyed; energy can only be transferred or changed from one form to another therefore du is zero. dq = dw this means that the entire heat supplied is converted into work (on the surroundings)
However, some of the heat supplied is also used to increase the internal energy of the system
Answer:
2 moles of Sn are produced when 4 moles of H2(g) are consumed completely
Explanation:
to determine the number of moles of sn (l) produced when 4.0 moles of H2 (g) is consumed completely.
First, find the number of moles of H2 consumed by taking this as limiting reagent.
Then find the moles of Sn (l) taking into account the stoichiometric relationship between H2(g) and Sn(l). 2:1
(s) + 2
(g) ⇒ Sn(l) + 2
(g)
∴2 moles of Sn are produced when 4 moles of H2(g) are consumed completely.
Answer:
Chemical
Explanation:
Macromolecules are part of the chemical components of cells. For example, DNA, proteins, and lipids.
Cells of similar types/function form tissues. Different types of tissues interact together to form organs. Organs form a common function.
To get the molarity, you divide the moles of solute by the litres of solution.
Molarity
=
moles of solute
litres of solution
For example, a 0.25 mol/L NaOH solution contains 0.25 mol of sodium hydroxide in every litre of solution.
To calculate the molarity of a solution, you need to know the number of moles of solute and the total volume of the solution.
To calculate molarity:
Calculate the number of moles of solute present.
Calculate the number of litres of solution present.
Divide the number of moles of solute by the number of litres of solution.
Answer:
P₂ = 130.18 kPa
Explanation:
In this case, we need to apply the Gay-Lussack's law assuming that the volume of the container remains constant. If that's the case, then:
P₁/T₁ = P₂/T₂ (1)
From here, we can solve for the Pressure at 273 K:
P₂ = P₁ * T₂ / T₁ (2)
Now, all we need to do is replace the given data and solve for P₂:
P₂ = 340 * 273 / 713
<h2>
P₂ = 130.18 kPa</h2>
Hope this helps
