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abruzzese [7]
3 years ago
12

A student has a solution with a pH of 7. The student adds HF, hydrogen floride, to the solution, hoping to increases the pH of t

he solution. What is wrong with this student's approach?
Select one: A. You cannot change the pH of a solution. B. HF is an acid, so it will lower the pH of the solution. C. The pH of the solution is already as high as possible. D. The pH is 7, so the solution is already as acidic as possible.
Chemistry
1 answer:
Allushta [10]3 years ago
5 0
Low pH = high acidity.
HF has a very low pH, so when added to a solution, it will lower the pH of the solution and therefore make it more acidic. So the answer should be B.
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forsale [732]

Answer:

10.8 days (3 sig.figs.)

Explanation:

All radioactive decay is 1st order decay defined by the expression A = A₀e^-kt

which is solved for time of decay (t) => t = ln(A/A₀) / -k

A = final weight = 1.0 gram

A₀ = initial weight = 16.0 grams

k = rate constant = 0.693/t(1/2) = 0.693/2.69 days = 0.258 days⁻¹

t = ln(1/16) / -0.258da⁻¹ = (-2.77/-0.258) days = 10.74646792 days (calculator)

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4 0
2 years ago
Select the correct Answers.
Mandarinka [93]

Answer:

3. The temperatures of the two substances equalize.

Explanation:

  • As two objects at different temperatures are placed in contact, heat is transferred from the warmer to the cooler object until the temperature of the two objects be the same.
  • The amount of heat that is transferred from the warmer object is equal to the amount of heat that is transferred into the cooler object.
  • This is in agreement with the law of conservation of energy.
  • <em>So, the right choice is: 3. The temperatures of the two substances equalize. </em>

<em></em>

8 0
3 years ago
Read 2 more answers
If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? T
Veronika [31]

Answer:

m_{MnO_2}=21.2gMnO_2

Explanation:

Hello,

In this case, given the balanced reaction:

2MnO_4^-+2Mn(OH)_2\rightarrow 4MnO_2+2OH^-+H_2O

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

m_{MnO_2}=14.5gMnO_4^-*\frac{1molMnO_4^-}{118.9gMnO_4^-}*\frac{4MnO_2}{2molMnO_4^-}  *\frac{86.9gMnO_2}{1molMnO_2} \\\\m_{MnO_2}=21.2gMnO_2

Best regards.

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3 years ago
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tekilochka [14]
NH₄NO₃
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(NH₄)₂SO₃
(NH₄)₃PO₄
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How do different types of waves make particles of matter move
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6 0
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