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Sunny_sXe [5.5K]
3 years ago
9

What’s greater 8^0 and 8^-2

Mathematics
1 answer:
lbvjy [14]3 years ago
5 0

Answer:

8^0 is greater than 8^-2.

Step-by-step explanation:

Anything to the power of 0 is 1 and 8^-2 is about 0.015625.

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After a 15% reduction, the sale price of a car is £13175. What was the
OlgaM077 [116]

Answer:

<u>The original price of the car was 11198.75</u>

Step-by-step explanation:

Hope it helps!

6 0
1 year ago
I NEED HELP ASAP PLEASE!!!
Alex17521 [72]

Answer:

Q2: -17

Q3: a) -5/2  b) g = -13

Step-by-step explanation:

2w+7 = -9

2w = -9 - 7

w = -16/2

w = -8

---

15 - 4w

= 15 - 4(-8)

= 15 - 32

= -17

----------------------

Q3:

a) 3/4(16m-24) = -48

16m -24 = -48 ÷ 3/4

16m = -64 + 24

16m = -40

m = -5/2

b) -20 = 1/6(36+12g)

-20 = 1/6 × 6(6+2g)

(cross out the 6 from 1/6 and 6)

-20 = 6 + 2g

-20-2g= 6

-2g = 6+20

-2g = 26

g = 26/-2

g = -13

3 0
3 years ago
If sin yº = 7/q and tan yº = 7/r , what is the value of cos yº? (6 points)
olya-2409 [2.1K]

Answer:

cos r/q is the answer,

Step-by-step explanation:

this can be seen when you elaborate sin=opposite/hypotenus and tan=opposite/adjacent by referring to the right angle triangle .

then, apply values of adjacent dan hypotenuse to cos

4 0
3 years ago
Use distributive property to factor method 1. Use distributive property to expand method 2.
sasho [114]

Step-by-step explanation:

I guess method 1 means to deal with whole factors.

x + 5 = (x - 2)(x + 5)

for (x + 5) <> 0 we can divide both sides by this factor :

1 = x - 2

x = 3

for the second solution we deal with

x + 5 = 0

x = -5

so, for x = -5 and x = 3 both functions deliver the same output, and these are the intersection points.

method 2 : we multiply the expression out and solve it then

x + 5 = (x - 2)(x + 5)

x + 5 = x² + 5x - 2x - 10 = x² + 3x - 10

0 = x² + 2x - 15

the general solution to such a square equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = 2

c = -15

x = (-2 ± sqrt(2² - 4×1×-15))/(2×1) =

= (-2 ± sqrt(4 + 60))/2 = (-2 ± sqrt(64))/2 = (-2 ± 8)/2 =

= -1 ± 4

x1 = -1 + 4 = 3

x2 = -1 - 4 = -5

and you get the 2 solutions again. as expected, they are the same as with method 1, of course.

4 0
2 years ago
Are there 5 100s in 0.305?
34kurt

no, 5 is in the thousandths place

4 0
3 years ago
Read 2 more answers
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